The probability that a randomly selected x-value from the distribution will be in the interval:
- P(35 < x < 45) = 0.6827 and,
- P(30 < x < 40) = 0.47725
<h3>What is the probability of a normal distribution?</h3>
The probability of a normal distribution can be determined from the symmetrical curve between 1 to 100%.
From the information given:
- Mean = 40
- Standard deviation = 5
To determine the probability that a randomly selected x-value is in the given interval:
![\mathbf{P(35 < x < 45) = P[Z\le 1] -P[Z\le -1]}](https://tex.z-dn.net/?f=%5Cmathbf%7BP%2835%20%3C%20x%20%3C%2045%29%20%3D%20P%5BZ%5Cle%201%5D%20-P%5BZ%5Cle%20-1%5D%7D)
Using normal distribution table:
P(35 < x < 45) = 0.8414 - 0.1587
P(35 < x < 45) = 0.6827
![\mathbf{P(30 < x < 40) = P[Z\le0]-P[Z\le -2]}](https://tex.z-dn.net/?f=%5Cmathbf%7BP%2830%20%3C%20x%20%3C%2040%29%20%3D%20P%5BZ%5Cle0%5D-P%5BZ%5Cle%20-2%5D%7D)
Using normal distribution table:
P(30 < x < 40) = 0.5 - 0.02275
P(30 < x < 40) = 0.47725
Learn more about the probability of a normal distribution here:
brainly.com/question/4079902
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Answer:
1. x + 24 = 3x
24 = 3x - x
24 = 2x
12 = x
3x
3 (12)
36
2. 10x - 27 = 7x
10x - 7x = 27
3x = 27
x = 9
7x
7 (9)
63
3. 5x + 1 = 6x - 13
5x - 6x = -13 - 1
-x = -14
x = 14
5x + 1
5 (14) + 1
71
4. 6x + 3 = 4x + 39
6x - 4x = 39 - 3
2x = 36
x = 18
6x + 3
6 (18) + 3
111
1. B
2. A
3. H
4. E
The answer, at least what I got, is 17.375 . They'd have to open an eighteenth package because the extra .375 is not in the original package, so I would go with B .
____________________ 4×^2
Answer:
5
Step-by-step explanation:
we should first write out what this equation looks like
|-2 + -3|
then you add -2 and - 3
-2 + -3 = -5
|-5|
now you find the absolute value of |-5|
|-5| = 5
that is your answer
