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Morgarella [4.7K]
3 years ago
6

Someone PLZ PLZ PLZ! Solve this

Mathematics
1 answer:
Firdavs [7]3 years ago
6 0

Answer: x = -3, y = 2, z = 4

Step-by-step explanation:

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Plz help its so confusing
aleksklad [387]

Answer:

20, 4

Step-by-step explanation:

Let's assume total number of students registered is n

Last week n/4 people are absent

so people present are n - n/4 = <u>3n/4</u>

Today after return of Jen  1/5 n are absent

so people present are n - n/5 = 4n/5

which is also equal to last week present people + 1 (Jen)

= 3n/4 + 1

= (3n + 4) / 4

so (3n + 4) / 4 = 4n/5

=> 3n + 4 = 4n/5 * 4

=> (3n + 4) * 5 = 16n

=> 15n + 20 = 16n

=> 20 = n

=> n = 20

So total students registered for class is 20

today no of people absent = n/5 = 20/5 = 4

8 0
3 years ago
A-(buc)=(A-b)u(A-c)<br>​
kupik [55]

Step-by-step explanation:

I don't get the question a bit but I hope this makes sense

:)

5 0
3 years ago
Find the slope between the points (-5,1) and (-1,-6)
madam [21]

Answer:

- 7 / 4

Step-by-step explanation:

Slope = (y2 - y1) / (x2 - x1)

Slope = (1 - -6) / (-5 - -1)

Slope = - 7 / 4

6 0
3 years ago
Read 2 more answers
Answer any Quetion in slope intercept form to represent a line that includes the points (3,-4) and (5,2). Complete explanation o
Ray Of Light [21]
Hopes this helps......

7 0
3 years ago
Which statement(s) is (are) correct?
Anna71 [15]

Answer:

<em>statements 3 and 4 are correct.</em>

Step-by-step explanation:

(1)

The probability of choosing cured pasta and bear= probability that the card is king.

Hence, The probability of choosing cured pasta and bear=\dfrac{4}{52}=\dfrac{1}{13}

Probability of choosing baked cucumber and lime mutton=probability that the card is 3.

as there are 4 cards that are '3'.

Hence Probability of choosing baked cucumber and lime mutton=\dfrac{4}{52}=\dfrac{1}{13}

as both the probabilities are equal.

Hence statement 1 is incorrect.

(2)

The probability of choosing gooseberry & passion fruit cheesecake= Probability taht the card is ace.

as there are 4 cards which are ace out of 52 cards.

Hence, The probability of choosing gooseberry & passion fruit cheesecake=\dfrac{4}{52}=\dfrac{1}{13}

probability of choosing poached fennel & lemon alligator=Probability that the card is a face card.

As there are 12 face cards out of 52 cards.

Hence, probability of choosing poached fennel & lemon alligator=\dfrac{12}{52}=\dfrac{3}{13}

Hence, the probability of choosing gooseberry and passion fruit cheesecake is smaller than the probability of choosing poached fennel & lemon alligator.

Hence statement 2 is false.

(3)

The probability of choosing a praline wafer=probability that the card is a diamond.

as there are 13 diamond cards out of 52 cards.

The probability of choosing a praline wafer=\dfrac{13}{52}=\dfrac{1}{4}

the probability of choosing poached fennel & lemon alligator=Probability that the card is a face card.

As there are 12 face cards out of 52 cards.

Hence, probability of choosing poached fennel & lemon alligator=\dfrac{12}{52}=\dfrac{3}{13}

Hence, The probability of choosing a praline wafer is greater than the probability of choosing poached fennel & lemon alligator.

Hence statement 3 is correct.

(4)

The probability of choosing pressure-cooked mushroom & garlic chicken =probability that the card is red.

As there are 26 red cards out of 52 cards.

Hence,  

The probability of choosing pressure-cooked mushroom & garlic chicken =\dfrac{26}{52}=\dfrac{1}{2}

probability of choosing an oven-baked apple & lavender calzone =probability that the card is black.

As there are 26 red cards out of 52 cards.

Hence,  probability of choosing an oven-baked apple & lavender calzone=\dfrac{26}{52}=\dfrac{1}{2}

Hence, The probability of choosing pressure-cooked mushroom & garlic chicken and the probability of choosing an oven-baked apple & lavender calzone are the same.

Hence statement 4 is true.

(5)

The probability of choosing pressure-cooked mushroom & garlic chicken =probability that the card is red.

As there are 26 red cards out of 52 cards.

Hence,  

The probability of choosing pressure-cooked mushroom & garlic chicken =\dfrac{26}{52}=\dfrac{1}{2}

the probability of choosing a praline wafer=probability that the card is a diamond.

as there are 13 diamond cards out of 52 cards.

The probability of choosing a praline wafer=\dfrac{13}{52}=\dfrac{1}{4}

Hence, the probability of choosing pressure-cooked mushroom & garlic chicken and the probability of choosing a praline wafer are not same.

Hence, statement 5 is not correct.


6 0
4 years ago
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