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Elden [556K]
3 years ago
8

How do I solve the equation (x+3)^1/2-1=x

Mathematics
1 answer:
konstantin123 [22]3 years ago
8 0

Answer:

Step-by-step explanation:

(x+3)^{\frac{1}{2} } -1=x\\(x+3)^{\frac{1}{2} } =x+1\\squaring\\x+3=x^2+2x+1\\\\x^{2} +2x-x+1-3=0\\x^2+x-2=0\\x^2+2x-x-2=0\\x(x+2)-1(x+2)=0\\(x+2)(x-1)=0\\x=-2,1

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PLEASE HELP!!!<br> If f(x) = -2x^2 + x - 5, what is f(3)?
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Answer:

  • <u>f(3) = -10</u>

Step-by-step explanation:

<u>Given</u>

  • f(x) = -2x² + x - 5

<u>Solving</u>

  • To find f(3), substitute x = 3 in the function
  • ⇒ f(3) = -2(3)² + (3) + 5
  • ⇒ f(3) = -2(9) + 8
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How to solve using substitution<br> y=3/4X+5<br> 4x-3y=-1
Pachacha [2.7K]
Please, use parentheses to enclose each fraction:
y=3/4X+5 should be written as <span>y=(3/4)X+5

Let's eliminate the fraction 3/4 by multiplying the above equation through by 4:

4[y] = 4[(3/4)x + 5]
Then 4y = 3x + 20
(no fraction here)

Let 's now solve the system   

4y=3x + 20
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We are to solve this system using subtraction.  To accomplish this, multiply the first equation by 3 and the second equation by 4.  Here's what happens:

12y = 9x + 60  (first equation)
16x-12y = -4, or -12y = -4 - 16x (second equation)

Then we have 

 12y = 9x + 60
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If we add here, 12y-12y becomes zero and we then have 0 = -7x + 56.
Solving this for x:  7x = 56; x=8

We were given equations   
</span><span>y=3/4X+5
4x-3y=-1

We can subst. x=8 into either of these eqn's to find y.  Let's try the first one:

y = (3/4)(8)+5 = 6+5=11

Then x=8 and y=11.

You should check this result.  Subst. x=8 and y=11 into the second given equation.  Is this equation now true?</span>
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