3 years ago

How do I solve the equation (x+3)^1/2-1=x

Mathematics

1 answer:

konstantin123 [22]3 years ago

8 0

Answer:

Step-by-step explanation:

$(x+3)^{\frac{1}{2} } -1=x\\(x+3)^{\frac{1}{2} } =x+1\\squaring\\x+3=x^2+2x+1\\\\x^{2} +2x-x+1-3=0\\x^2+x-2=0\\x^2+2x-x-2=0\\x(x+2)-1(x+2)=0\\(x+2)(x-1)=0\\x=-2,1$

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