The similar circles P and Q can be made equal by dilation and translation
- The horizontal distance between the center of circles P and Q is 11.70 units
- The scale factor of dilation from circle P to Q is 2.5
<h3>The horizontal distance between their centers?</h3>
From the figure, we have the centers to be:
P = (-5,4)
Q = (6,8)
The distance is then calculated using:
d = √(x2 - x1)^2 + (y2 - y1)^2
So, we have:
d = √(6 + 5)^2 + (8 - 4)^2
Evaluate the sum
d = √137
Evaluate the root
d = 11.70
Hence, the horizontal distance between the center of circles P and Q is 11.70 units
<h3>The scale factor of dilation from circle P to Q</h3>
We have their radius to be:
P = 2
Q = 5
Divide the radius of Q by P to determine the scale factor (k)
k = Q/P
k = 5/2
k = 2.5
Hence, the scale factor of dilation from circle P to Q is 2.5
Read more about dilation at:
brainly.com/question/3457976
Answer:
40/71
Step-by-step explanation:
Because 71 is prime so there is no other way to simplify
Answer:
a dollar 1.50
Step-by-step explanation:
you take 4 and multiple by 1.25 which is 5 then you the remaining 3 and divide by 2 which is 1.50
Hope this helps:)
Answer:
x = -6; v = 4.
Step-by-step explanation:
–14 = –(-2x + 2)
-14 = 2x - 2
2x - 2 = -14
2x = -12
x = -6.
51 = 7(-1 + 2v) + 2
51 = -7 + 14v + 2
51 = 14v - 5
14v = 56
v = 4.
Hope this helps!
