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3 years ago

The perimeter of an equilateral triangle is at most 72, what would this be as an inequality?

Mathematics

1 answer:

Reptile [31]3 years ago

6 0

at most is either that number or less

so x<=72 would be the inequality

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8x = 96<br> How would I solve for x

Vaselesa [24]

How to solve your problem

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2 years ago

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Mark and peter went to an arcade where the machines took tokens. Marilk played 9 games of ping pong and 5 games of pinball, usin

Readme [11.4K]

Answer:

9x + 5y = 29 ........... (1) and

3x + y = 7 ........... (2)

Each game of ping pong requires 1 number of token and each game of pinball requires 4 number of tokens.

Step-by-step explanation:

Let, each game of ping pong requires x number of tokens and each game of pinball requires y number of tokens.

So, from the given conditions we can write

9x + 5y = 29 ........... (1) and

3x + y = 7 ........... (2)

Now, solving equations (1) and (2) we get,

9x + 5(7 - 3x) = 29

⇒ 35 - 6x = 29

⇒ 6x = 6

⇒ x = 1 token.

Now, putting x = 1 in equation (2) we get,

3 + y = 7

⇒ y = 4 tokens.

So, each game of ping pong requires 1 number of token and each game of pinball requires 4 number of tokens. (Answer)

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3 years ago

PLEASE help due today Geometry

irina1246 [14]

$\\ \sf\Rrightarrow \dfrac{15}{20}=\dfrac{21}{28}$

$\\ \sf\Rrightarrow \dfrac{1}{4}=\dfrac{1}{4}$

Hence they are similar

<A=<H
And ratio of sides are same

Hence both triangles are similar by SAS property

$\\ \sf\Rrightarrow ∆KDH\sim ∆ABD$

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2 years ago

10y-12=4<br> Help??? Confused??? Trying to make this twenty letters long lol

ruslelena [56]

If you need to solve for y
10y-12=4
10y=12+4
10y=16
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4 0

3 years ago

Read 2 more answers

A rancher wants to fence in an area of 1500000 square feet in a rectangular field and then divide it in half with a fence down t

VLD [36.1K]

Answer:

6000 ft

Step-by-step explanation:

Let length of rectangular field=x

Breadth of rectangular field=y

Area of rectangular field= $1500000$ square ft

Area of rectangular field= $l\times b$

Area of rectangular field= $x\time y$

$1500000=xy$

$y=\frac{1500000}{x}$

Fencing used ,P(x)= $x+x+y+y+y=2x+3y$

Substitute the value of y

P(x)= $2x+3(\frac{1500000}{x})$

$P(x)=2x+\frac{4500000}{x}$

Differentiate w.r.t x

$P'(x)=2-\frac{4500000}{x^2}$

Using formula: $\frac{dx^n}{dx}=nx^{n-1}$

$P'(x)=0$

$2-\frac{4500000}{x^2}=0$

$\frac{4500000}{x^2}=2$

$x^2=\frac{4500000}{2}=2250000$

$x=\sqrt{2250000}=1500$

It is always positive because length is always positive.

Again differentiate w.r.t x

$P''(x)=\frac{9000000}{x^3}$

Substitute x=1500

$P''(1500)=\frac{9000000}{(1500)^3}>0$

Hence, fencing is minimum at x=1 500

Substitute x=1 500

$y=\frac{1500000}{1500}=1000$

Length of rectangular field=1500 ft

Breadth of rectangular field=1000 ft

Substitute the values

Shortest length of fence used= $2(1500)+3(1000)=6000 ft$

Hence, the shortest length of fence that the rancher can used=6000 ft

3 0

3 years ago