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kompoz [17]
2 years ago
7

Im confused, not sure how to do this. Please help me it is geometry, specifically perpendicular lines with an equation and a poi

nt

Mathematics
1 answer:
marishachu [46]2 years ago
7 0
The line y = -3 is a horizontal line. The perpendicular line will be vertical, so will have an equation of the form
  x = c
for some constant c.

You want the vertical line to go through the point (4, -6), so the required value of c is the x-value of that point: 4

Your equation is
  x = 4

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A principal of $1800 is invested at 8.5% interest, compounded annually. How much will the investment be worth after 11 years?
posledela
Calc= 1800 times (0.085 ^11)
3 0
2 years ago
Determine the number of possible triangles, ABC, that can be formed given A = 30°, a = 7, and b = 18.
zzz [600]

Answer:

none

Step-by-step explanation:

We are given a triangle ABC with ∠A = 30°, sides a = 4 and b = 10.

According to the 'Law of Sines- Ambiguous Case', we have,

If a < b×sinA, then no triangle is possible.

If a = b×sinA, only one triangle is possible

If a > b×sinA, two triangles are possible.

So, we have,

b×sinA = 10 × sin30 = 10 × 0.5 = 5.

Now, as

4 = a < bsinA = 5.

We get, according to the rule, no triangle is possible.

8 0
2 years ago
For $ (x) = 2x+1 and g(x) = x - 7, find (f •g)(2).
blondinia [14]

Answer:

3x - 14

Step-by-step explanation:

f = 2x + 1

2x + 1 * g

g = x - 7

2x + 1 * x - 7 = 3x - 7

3x - 7 * 2 = 3x - 14

Comments:

Hope this helped (:

also I assumed the $ = f at the begining so please let me know if I am wrong

7 0
3 years ago
1. What is the slope of a line that is parallel to the line represented by the equation y=-2/5x + 4/5
lbvjy [14]

Hi student, let me help you out! :)

. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .  . . . . . . . . .

We are asked to find the slope of the line that is parallel to the line \star~\mathrm{y=-\cfrac{2}{5}x+\cfrac{4}{5}}.

\triangle~\fbox{\bf{KEY:}}

  • Parallel lines have the same slope.

So let's first determine the slope of the first line, and then let's find the slope of the line that's parallel to it.

\circ\!\!\!\star\mathcal{HINT:}

  • The slope is the coefficient of x.

So the slope is

\star~\mathrm{-\cfrac{2}{5}}.

Can you guess the slope of the line that is parallel to the first line?

That's right! The slope is...

\star~\mathrm{-\cfrac{2}{5}}

Hope it helps you out! :D

Ask in comments if any queries arise.

#StudyWithBrainly

~Just a smiley person helping fellow students :)

4 0
2 years ago
Round to the nearest hundredth.<br><br> I need to be walked through the steps :)
Mamont248 [21]
It's 45 because they are congruent. If the vertex is in the center of a circle then the angle and the arc are congruent
6 0
3 years ago
Read 2 more answers
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