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nikitadnepr [17]
3 years ago
12

A store sells bouquets of fruits for $10 a bouquet. The daily cost to produce x bouquets of fruits is defined by the function f(

x) = – x 4 + 3x 3 + 5x 2 + 20x + 1.
Mathematics
2 answers:
devlian [24]3 years ago
3 0

Answer:

5 or C

Step-by-step explanation:

when you plug in 5, you get -24 as the cost. Then you take that number with the amount of money you make selling 5 flowers and that would be $50 since they are $10/per bouquet. Then when you subtract you get a positive profit of $26.

Nonamiya [84]3 years ago
3 0

Answer:

5

Step-by-step explanation:

For profit to be had, the selling price (represented by $10x, x being number of bouquets sold) must be greater than the cost to produce (here, -x^4 + 3x^3 + 5x^2 + 20x +1).

Set up an inequality such that 10x is greater than the cost to produce.

10x > -x^4 + 3x^3 + 5x^2 + 20x + 1

-Solving the inequality by subtracting 10x from both sides, we have:

0 > -x^4 + 3x^3 + 5x^2 + 10x + 1

-Using a graphing calculator, (the one they give you on Edgenuity) graph the new function and look for where the graph is below the x axis. (y is less than 0)

Looking at the graph, we see that when x is greater than 0, (you can't sell a negative amount of bouquets) y is greater than 0 up until x = 4.579. After 4.579, the y values become negative. (what we want to be looking at according to the inequality.)

You can't sell 4.579 bouquets, and even if you could, you'd be breaking even, with y=0. The answer isn't 4, because according to the graph and inequality, y would be greater than 0 (making the inequality false). Because of this, we have to find the next whole positive number that would make the inequality true, and that is 5.

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Answer:

Since M1 has the higher probability of being in the desired range, we choose M1.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Two machines M1, M2 are used to manufacture resistors with a design specification of 1000 ohm with 10% tolerance.

So we need the machines to be within 1000 - 0.1*1000 = 900 ohms and 1000 + 0.1*1000 = 1100 ohms.

For each machine, we need to find the probabilty of the machine being in this range. We choose the one with the higher probability.

M1:

Resistors of M1 are found to follow normal distribution with mean 1050 ohm and standard deviation of 100 ohm. This means that \mu = 1050, \sigma = 100

The probability is the pvalue of Z when X = 1100 subtracted by the pvalue of Z when X = 900. So

X = 1100

Z = \frac{X - \mu}{\sigma}

Z = \frac{1100 - 1050}{100}

Z = 0.5

Z = 0.5 has a pvalue of 0.6915.

X = 900

Z = \frac{X - \mu}{\sigma}

Z = \frac{900 - 1050}{100}

Z = -1.5

Z = -1.5 has a pvalue of 0.0668

0.6915 - 0.0668 = 0.6247.

M1 has a 62.47% probability of being in the desired range.

M2:

M2 are found to follow normal distribution with mean 1000 ohm and standard deviation of 120 ohm. This means that \mu = 1000, \sigma = 120

X = 1100

Z = \frac{X - \mu}{\sigma}

Z = \frac{1100 - 1000}{120}

Z = 0.83

Z = 0.83 has a pvalue of 0.7967.

X = 900

Z = \frac{X - \mu}{\sigma}

Z = \frac{900 - 1000}{120}

Z = -0.83

Z = -0.83 has a pvalue of 0.2033

0.7967 - 0.2033 = 0.5934

M2 has a 59.34% probability of being in the desired range.

Since M1 has the higher probability of being in the desired range, we choose M1.

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Step-by-step explanation:

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