Complete the square and wright in standard form x^2+y^2-8x-12+52=36

2 answers:

5 0

X² + y² - 8x - 12y + 52 = 36
x² - 8x + y² - 12y + 52 = 36
x² - 8x + y² - 12y = 88
(x² - 8x + 16) + (y² - 12y + 36) = 88 + 16 + 36
(x - 4)² + (y - 6)² = 138
(h, k) = (x, y) = (4, 6)

mixas84 [53]3 years ago

5 0

$x^2+y^2-8x-12y+52=36 \\
x^2-8x+16+y^2-12y+36-16-36+52=36 \\
(x-4)^2+(y-6)^2-52+52=36 \\
\boxed{(x-4)^2+(y-6)^2=36}$

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