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mars1129 [50]
3 years ago
12

Complete the square and wright in standard form x^2+y^2-8x-12+52=36

Mathematics
2 answers:
Sphinxa [80]3 years ago
5 0
X² + y² - 8x - 12y + 52 = 36
x² - 8x + y² - 12y + 52 = 36
x² - 8x + y² - 12y = 88
(x² - 8x + 16) + (y² - 12y + 36) = 88 + 16 + 36
(x - 4)² + (y - 6)² = 138
(h, k) = (x, y) = (4, 6)

mixas84 [53]3 years ago
5 0
x^2+y^2-8x-12y+52=36 \\
x^2-8x+16+y^2-12y+36-16-36+52=36 \\
(x-4)^2+(y-6)^2-52+52=36 \\
\boxed{(x-4)^2+(y-6)^2=36}
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-4(x - 2) - 3x = 2(5x - 7) + 6
Allisa [31]

Answer: last option.

Step-by-step explanation:

To apply the Distributive property, remember that:

c(a-b)=ca-cb

Then, applying this, you get:

-4(x - 2) - 3x = 2(5x - 7) + 6\\\\(-4)(x)+(-4)(-2)-3x=(2)(5x)+(2)(-7)+6\\\\-4x+8-3x=10x-14+6

Combine like terms means that you need to add the like terms.

Therefore, you get:

-7x+8=10x-8

You can observe that the expression obtained matches with the expression provided in the last option.

3 0
3 years ago
1) Easton went to a concert with some
tatuchka [14]
Subtract the 15 from the 133
you get 118
divide 29.50 from the 118
you get 4
4 people went to the concert
7 0
3 years ago
A candy company claims that 20% of the candies in its bags are colored green. Steve buys 30 bags of 30 candies, randomly selects
Allisa [31]

Answer:

The probability of Steve agreeing with the company’s claim is 0.50502.

Step-by-step explanation:

Let <em>X</em> denote the number of green candies.

The probability of green candies is, <em>p</em> = 0.20.

Steve buys 30 bags of 30 candies, randomly selects one candy from each, and counts the number of green candies.

So, <em>n</em> = 30 candies are randomly selected.

All the candies are independent of each other.

The random variable <em>X</em> follows a binomial distribution with parameter <em>n</em> = 30 and <em>p</em> = 0.20.

It is provided that if there are 5, 6, or 7 green candies, Steve will conclude that the company’s claim is correct.

Compute the probability of 5, 6 and 7 green candies as follows:

P(X=5)={30\choose 5}(0.20)^{5}(1-0.20)^{30-5}=0.17228\\\\P(X=6)={30\choose 6}(0.20)^{6}(1-0.20)^{30-6}=0.17946\\\\P(X=7)={30\choose 7}(0.20)^{7}(1-0.20)^{30-7}=0.15328

Then the probability of Steve agreeing with the company’s claim is:

P (Accepting the claim) = P (X = 5) + P (X = 6) + P (X = 7)

                                       = 0.17228 + 0.17946 + 0.15328

                                       = 0.50502

Thus, the probability of Steve agreeing with the company’s claim is 0.50502.

7 0
3 years ago
Rockwell hardness of pins of a certain type is known to have a mean value of 50 and a standard deviation of 1.2.a. If the distri
zalisa [80]

Answer:

a

 P(\= X \ge 51 ) =0.0062

b

P(\= X \ge 51 ) = 0

Step-by-step explanation:

From the question we are told that

The mean value is \mu = 50

The standard deviation is  \sigma = 1.2

Considering question a

The sample size is  n = 9

Generally the standard error of the mean is mathematically represented as

      \sigma_x = \frac{\sigma }{\sqrt{n} }

=>   \sigma_x = \frac{ 1.2 }{\sqrt{9} }

=>  \sigma_x = 0.4

Generally the probability that the sample mean hardness for a random sample of 9 pins is at least 51 is mathematically represented as

      P(\= X \ge 51 ) = P( \frac{\= X - \mu }{\sigma_{x}}  \ge \frac{51 - 50 }{0.4 } )

\frac{\= X -\mu}{\sigma }  =  Z (The  \ standardized \  value\  of  \ \= X )

     P(\= X \ge 51 ) = P( Z  \ge 2.5 )

=>   P(\= X \ge 51 ) =1-  P( Z  < 2.5 )

From the z table  the area under the normal curve to the left corresponding to  2.5  is

    P( Z  < 2.5 ) = 0.99379

=> P(\= X \ge 51 ) =1-0.99379

=> P(\= X \ge 51 ) =0.0062

Considering question b

The sample size is  n = 40

   Generally the standard error of the mean is mathematically represented as

      \sigma_x = \frac{\sigma }{\sqrt{n} }

=>   \sigma_x = \frac{ 1.2 }{\sqrt{40} }

=>  \sigma_x = 0.1897

Generally the (approximate) probability that the sample mean hardness for a random sample of 40 pins is at least 51 is mathematically represented as  

       P(\= X \ge 51 ) = P( \frac{\= X - \mu }{\sigma_x}  \ge \frac{51 - 50 }{0.1897 } )

=> P(\= X \ge 51 ) = P(Z  \ge 5.2715  )

=>  P(\= X \ge 51 ) = 1- P(Z < 5.2715  )

From the z table  the area under the normal curve to the left corresponding to  5.2715 and

=>  P(Z < 5.2715  ) = 1

So

   P(\= X \ge 51 ) = 1- 1

=> P(\= X \ge 51 ) = 0

5 0
3 years ago
A 500.-kilogram roller coaster starts from rest at the top of an 80.0-meter hill. What is its potential enegy halfway down the h
Anastaziya [24]

Answer:

the answer is 200kg


Step-by-step explanation:


8 0
3 years ago
Read 2 more answers
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