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3 years ago

Complete the square and wright in standard form x^2+y^2-8x-12+52=36

2 answers:

5 0

X² + y² - 8x - 12y + 52 = 36
x² - 8x + y² - 12y + 52 = 36
x² - 8x + y² - 12y = 88
(x² - 8x + 16) + (y² - 12y + 36) = 88 + 16 + 36
(x - 4)² + (y - 6)² = 138
(h, k) = (x, y) = (4, 6)

mixas84 [53]3 years ago

5 0

$x^2+y^2-8x-12y+52=36 \\
x^2-8x+16+y^2-12y+36-16-36+52=36 \\
(x-4)^2+(y-6)^2-52+52=36 \\
\boxed{(x-4)^2+(y-6)^2=36}$

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Oksana_A [137]

Answer:

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Step-by-step explanation:

Applying the squaring rule to each of the elements of the domain, we get ...

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1. There are 7 different numbers in the Domain list.

2. See above

3. There are 5 different numbers in the Range list.

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2 years ago

A random sample of 70 printers discovered that 25 of them were being used in small businesses. find the 95% limit for the popula

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The sample proportion of printers used in small business is:

$\hat{p}=\frac{25}{70}=0.3571$

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$\hat{p} \pm z_{\frac{0.05}{2}} \sqrt{\frac{\hat{p}(1-\hat{p})}{n} }$

Where:

$z_{\frac{0.05}{2}}=1.96$ is the critical value at 0.05 significance level

$\therefore 0.3571 \pm 1.96 \sqrt{\frac{0.3571(1-0.3571)}{70} }$

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$\left ( 0.3571 - 0.1122, 0.3571 + 0.1122 \right)$

$\left(0.245,0.469 \right)$

Therefore, the 95% confidence interval for the population proportion of printers that are used in small businesses is (0.245 , 0.469)

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Answer:

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