In a quadratic function, $f(x)= ax^2+bx+c$ the leading coefficient is $a$ , i.e. the coefficient of $x^2$ , and the constant term is $c$ , i.e. the coefficient without any power of $x$ .

So, if you want leading coefficient 2 and constant term -3, your function needs to be like

$f(x)=2x^2+bx-3$

for any value of $b$ . Among your options:

The first is not a quadratic (it starts with $x^3$ )
The second has leading term -3 and constant term 2
The third is not a quadratic (same as the first)
The last is correct.

4 0

3 years ago

There are 12 bags of apples on a market stall.

Mariana [72]

Answer:

The number of apples in the 12 bag is 96

Solution:

Given that, there are 12 bags of apples on a market stall.

The mean number of apples in each bag is 8.

We have to calculate the number of apples in the 12 bag.

The mean of "n" observations is given as:

Hence, there are 96 apples in 12 bags.

3 0

2 years ago

I need help ASAP <br> 120>10n+20

Burka [1]

Answer:n = 10 can make the inequality true

Step-by-step explanation:

The given inequality is

120 greater than or equal to 10n + 20. This means that the least value of n that would make the inequality true would be 10.

If we substitute n = 10 into the right hand side of the given inequality, it would result to 120.

So n = 10 can make the inequality true.

4 0

3 years ago

What is the gcf of 12 78 and 90

Anuta_ua [19.1K]

The greatest common factor of 12, 78, and 90 is 6.

Factors are the numbers, that when multiplied with another number, equal the product.

Factors of 12: 1, 2, 3, 4, 6, and 12.
Factors of 78: 1, 2, 3, 6, 13, 26, 39, and 78.
Factors of 90: 1, 2, 3, 5, 6, 9, 10, 15, 18, 20, 45, and 90.

The Greatest Common Factor is the highest factor shared among the products. Thus proving 6 is the GCF.

I hope this helps!

7 0

3 years ago