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1 year ago

Which of the following values is greater than −3.5? −3.25 −3.75 −4.2 −5.4

Mathematics

1 answer:

fomenos1 year ago

6 0

The answer is -3.25 is greater :)

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8 to 11 do it with equations thx

Alenkasestr [34]

Answer:

Step-by-step explanation:

8. $4\geq x+\frac{3}{4}$

$4(4\geq x+\frac{3}{4} )$

$16\geq 4x + 3$

$-3$ $-3$

$13\geq 4x$

$\frac{13}{4}\geq \frac{4x}{4}$

$\frac{13}{4} \geq x = x\leq \frac{13}{4}$

$x\leq \frac{13}{4}=3.25$

9. $x-3\leq -8$

$+3$ $+3$

$x\leq -5}$

10. $4\leq x-7$

$+7$ $+7$

$11\leq x=x\geq 11$

11. 6.9 < x - 2.3

+ 2.3 + 2.3

9.2 < x = x > 9.2

Hope this helps!

5 0

2 years ago

Cameron created a composite figure by stacking three cubes the cubes measure 2 inches on each side what is the volume of the c

8090 [49]

Answer:

24 cubic inches.

Step-by-step explanation:

The volume of one cube = s * s * s or s^3

s = 2 inches

V = s^3

V = 2 * 2 * 2 or 2^3

V = 8 cubic inches.

The volume of 3 of them is 8*3 = 24 cubic inches.

8 0

2 years ago

The sum of 2 times a number and 3 equals 4

skad [1K]

2(n+3)= 4

n= -1

-1+3=2 then 2x2=4. Sum is an answer to an addition problem so a number and 3 times 2 = 4. Hope this helps and have a great day!

3 0

3 years ago

Round to nearest tenth and solve for x

stepladder [879]

Answer:

$\displaystyle 9,6$

Step-by-step explanation:

$\displaystyle \frac{x}{6,4} = csc\:42 \hookrightarrow 6,4cot\:42 = x \hookrightarrow 9,5646499191... = x \\ \\ 9,6 ≈ x$

OR

$\displaystyle \frac{6,4}{x} = sin\:42 \hookrightarrow xsin\:42 = 6,4 \hookrightarrow \frac{6,4}{sin\:42} = x \hookrightarrow 9,5646499191... = x \\ \\ 9,6 ≈ x$

Information on trigonometric ratios

$\displaystyle \frac{OPPOCITE}{HYPOTENUSE} = sin\:θ \\ \frac{ADJACENT}{HYPOTENUSE} = cos\:θ \\ \frac{OPPOCITE}{ADJACENT} = tan\:θ \\ \frac{HYPOTENUSE}{ADJACENT} = sec\:θ \\ \frac{HYPOTENUSE}{OPPOCITE} = csc\:θ \\ \frac{ADJACENT}{OPPOCITE} = cot\:θ$

I am joyous to assist you at any time.

6 0

2 years ago

Find the volume V obtained by rotating the region bounded by the curves about the given axis.

BartSMP [9]

Using the disk method, the volume is given by the integral

$\displaystyle \pi \int_{\pi/2}^\pi (9\sin(x))^2\,\mathrm dx = 81\pi \int_{\pi/2}^\pi \sin^2(x)\,\mathrm dx$

That is, each disk has a radius of y = 9 sin(x) and hence area = π (9 sin(x))². Add up infinitely many such disks by integrating. Then the volume is

$\displaystyle 81\pi \int_{\pi/2}^\pi \sin^2(x)\,\mathrm dx = \frac{81\pi}2 \int_{\pi/2}^\pi (1-\cos(2x))\,\mathrm dx \\\\ =\frac{81\pi}2 \left(x-\frac{\sin(2x)}2\right)\bigg|_{\pi/2}^\pi \\\\ = \frac{81\pi}2 \left( \left(\pi-\frac{\sin(2\pi)}2\right) - \left(\frac\pi2 - \frac{\sin(\pi)}2\right) \right) \\\\ = \boxed{\frac{81\pi^2}4}$

8 0

2 years ago