Answer:
P(system works) = 0.6144
Step-by-step explanation:
Each compoent has an 80% = 0.8 probability of working correctly.
1 and 2
We need at least one of them working.
Either neither works, or at least one works.
Each one has a 1 - 0.8 = 0.2 probability of not working.
0.2*0.2 = 0.04
0.04 of neither working.
1 - 0.04 = 0.96 probability of at least one working
3 and 4
We need both to work, each with a 0.8 probability.
Calculate P(system works).
At least one of the first two, with 0.96 probability
3 and 4, each with 0.8 probability.
0.96*0.8*0.8 = 0.6144
So
P(system works) = 0.6144
1. x = -5
2. r = 40
3. m = 3
The 5 is on the ten thousand place.
Answer:
B
Step-by-step explanation:
