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alekssr [168]
3 years ago
7

Which equation is equivalent to the formula d = rt?r = d/tr = dtt = r/dt = dr​

Mathematics
1 answer:
Allisa [31]3 years ago
6 0

Step-by-step explanation:

d = rt

divide t

d/t = r

r = d/t

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What is the slope of the line that passes through the points (4, 8) and (-3, 1)?
blondinia [14]

Answer:

1

Step-by-step explanation:

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3 years ago
Given the following formula , solve for t.
hodyreva [135]

I think it’s c. Not sure though. Pure guess
4 0
3 years ago
What is the least common multiple of 10, 20, and 14?
lyudmila [28]

Answer:

The least common multiple would be 140.

Step-by-step explanation:

The least common multiple is known to be a multiple that is the lowest value that satisfies being a multiple with the other factors given.

The least common multiple was 140 as it was the lowest value that satisfied being a multiple of 14, 10, AND, 20,

14 * 10 = 140

20 * 7 = 140

10 * 14 = 140

7 0
3 years ago
Can someone please explain this to me? Thanks!
Makovka662 [10]

Answer:  Choice D

\displaystyle F\ '(x) = 2x\sqrt{1+x^6}\\\\

==========================================================

Explanation:

Let g(t) be the antiderivative of g'(t) = \sqrt{1+t^3}. We don't need to find out what g(t) is exactly.

Recall by the fundamental theorem of calculus, we can say the following:

\displaystyle \int_{a}^{b} g'(t)dt = g(b)-g(a)

This theorem ties together the concepts of integrals and derivatives to show that they are basically inverse operations (more or less).

So,

\displaystyle F(x) = \int_{\pi}^{x^2}\sqrt{1+t^3}dt\\\\ \displaystyle F(x) = \int_{\pi}^{x^2}g'(t)dt\\\\ \displaystyle F(x) = g(x^2) - g(\pi)\\\\

From here, we apply the derivative with respect to x to both sides. Note that the g(\pi) portion is a constant, so g'(\pi) = 0

\displaystyle F(x) = g(x^2) - g(\pi)\\\\ \displaystyle F \ '(x) = \frac{d}{dx}[g(x^2)-g(\pi)]\\\\\displaystyle F\ '(x) = \frac{d}{dx}[g(x^2)] - \frac{d}{dx}[g(\pi)]\\\\ \displaystyle F\ '(x) = \frac{d}{dx}[x^2]*g'(x^2) - g'(\pi) \ \text{ .... chain rule}\\\\

\displaystyle F\ '(x) = 2x*g'(x^2) - 0\\\\ \displaystyle F\ '(x) = 2x*g'(x^2)\\\\ \displaystyle F\ '(x) = 2x\sqrt{1+(x^2)^3}\\\\ \displaystyle F\ '(x) = \boldsymbol{2x\sqrt{1+x^6}}\\\\

Answer is choice D

5 0
2 years ago
Read 2 more answers
Evaluate the following expressions, and justify your answers.<br> WhatPower5(1)
Zepler [3.9K]

Answer:

correct answer is 0

Step-by-step explanation:

given data  as per question

WhatPower5(1)

to find out

Evaluate the expressions WhatPower5(1)

solution    

so here  we know that whatpower mean exponent of equation so we get by given equation  

so

we know whatpower5(1)  = 0

because  here

we know that  anything exponent 0 is equal to 0

so here we can say that

that is 5^{0} =  1

so that  the exponent  is here 0 of 5  that become 1

so correct answer is 0

5 0
3 years ago
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