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FinnZ [79.3K]
3 years ago
9

Find the equation of the line through (10, 4) that is parallel to the line with the equation

Mathematics
1 answer:
lyudmila [28]3 years ago
6 0

Answer:

x + y = 14

Step-by-step explanation:

Parallel lines have the same slope, so the line's slope will be -1.

Plug this slope and the given point into y = mx + b to find b:

y = mx + b

4 = -1(10) + b

4 = -10 + b

14 = b

Then, plug this and the slope into y = mx + b

y = -x + 14

Then, put this into standard form by moving the x to the other side:

x + y = 14 is the equation in standard form

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tatyana61 [14]
The answer is (4,-3.4)
3 0
3 years ago
Solve for x 5x - 10 = -10​
Zigmanuir [339]

Answer:

the answer is x = 0

Step-by-step explanation:

Cancel equal terms on both sides of the equation:

5x = 0

Divide both side of the equation by 5.

x = 0

Therefore, the answer is x = 0

3 0
3 years ago
Read 2 more answers
A container shapes like an inverted cone holds 96 cubic centimeters of water. The height of the cup is 14 centimeters. Find the
Korolek [52]

Answer:

Cone Volume = (PI * radius^2 * height) / 3

96 cc = (PI * radius^2 * 14) / 3

(96 * 3) / (PI * 14) = radius^2

radius ^ 2 = 6.5480890872

radius = 2.5589234235

diameter = radius *2 = 5.117846847  cm

diameter = 5.12 cm (rounded)

Step-by-step explanation:

5 0
2 years ago
A simple random sample of 90 is drawn from a normally distributed population, and the mean is found to be 138, with a standard d
bagirrra123 [75]

The 90% confidence interval for the population mean of the considered population from the given sample data is given by: Option C:  [130.10, 143.90]

<h3>
How to find the confidence interval for population mean from large samples (sample size > 30)?</h3>

Suppose that we have:

  • Sample size n > 30
  • Sample mean = \overline{x}
  • Sample standard deviation = s
  • Population standard deviation = \sigma
  • Level of significance = \alpha

Then the confidence interval is obtained as

  • Case 1: Population standard deviation is known

\overline{x} \pm Z_{\alpha /2}\dfrac{\sigma}{\sqrt{n}}

  • Case 2: Population standard deviation is unknown.

\overline{x} \pm Z_{\alpha /2}\dfrac{s}{\sqrt{n}}

For this case, we're given that:

  • Sample size n = 90 > 30
  • Sample mean = \overline{x} = 138
  • Sample standard deviation = s = 34
  • Level of significance = \alpha = 100% - confidence = 100% - 90% = 10% = 0.1 (converted percent to decimal).

At this level of significance, the critical value of Z is: Z_{0.1/2} = ±1.645

Thus, we get:

CI = \overline{x} \pm Z_{\alpha /2}\dfrac{s}{\sqrt{n}}\\CI = 138 \pm 1.645\times \dfrac{34}{\sqrt{90}}\\\\CI \approx 138 \pm 5.896\\CI \approx [138 - 5.896, 138 + 5.896]\\CI \approx [132.104, 143.896] \approx [130.10, 143.90]

Thus, the 90% confidence interval for the population mean of the considered population from the given sample data is given by: Option C:  [130.10, 143.90]

Learn more about confidence interval for population mean from large samples here:

brainly.com/question/13770164

3 0
2 years ago
They told her they charge $45 to install the cable box and $60 each month for the service.
Nady [450]
The answer is 2,700
This is because




60
x45
------------
300
+2400
--------------


Or Use Partial Products

60. 0. 1.0x40
___________. 2.60x40
I2400 I. 30. I.
40I. I. I. 3.0x40
|---------I----------I. 4.0x5
5I. 0. I. 0. I
l____ I______I
I hope this helped because this was a lot and I mean a lot of work


3 0
3 years ago
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