Answer:
y = 52.02
Step-by-step explanation:
Since this is a right triangle, we can use trig functions
cos theta = adj/ hyp
cos y = 8/13
Take the inverse cos of each side
cos ^-1 cos y = cos ^-1 ( 8/13)
y = cos ^-1 ( 8/13)
y = 52.02012756
To the nearest hundredth
y = 52.02
Answer: The consecutive angles with angle D are B and A.
Explanation:
It is given that DBCA is a quadrilateral. Since it is a quadrilateral it means the have 4 vertices and 4 angles D, B,C,A.
The angles are formed in the order of the figure name. If the quadrilateral name is DBCA, So the order of the angles are D,B,C,A. It means the angle immediate after D is B, the angle immediate after B is C, the angle immediate after C is A and the angle immediate after A is D.
If the quadrilateral name is DBCA it means the sides are DB, BC, CA and AD as shown in the figure.
Consecutive angles of D means the angle immediate before and after the angle D.
In the figure there are some types of quadrilateral and from the figure we can easily noticed that the consecutive angles with angle D are B and A.
Given: ∠ DEF
To construct: ∠TSZ ≅ ∠DEF
Construction: Consider the attachment
Step-01: Draw a line XY and choose a point S on it as a vertex of the required angle. Further marks point T such that DE = ST
Step-02: Take an arc AB from point E in ∠DEF of any length and draw at point S which cuts at point P on XY line.
Step-03: Take another arc of length AB from point B in ∠DEF and draw from point P which cuts to the previous arc at Q.
Step-04: Now, join the point SQ and extend up to Z such that EF = SZ
Hence, ∠ TSZ will be the required congruent constructed angle to∠DEF
Answer:
$ 1650
Step-by-step explanation:
Denise's child tax credit for 2017 = ( 2 × $ 1000) - ( ( $ 81500 -$ 75 000) / $ 1000 × $ 50 ) = $ 2000 - $ 350 = $ 1650 where 6.5 factor is rounded to nearest whole number
For Example 3 :
First blank is cos (theta)
Second blank is sec(theta)
For Example 4 :
First blank is (x^4)/(2) - (3x^2)
Second blank is 0
Third blank is -4
Fourth blank is 0.4286
Hope this helps :)