A(n) = a₁.(r)ⁿ⁻¹, where a₁ = 1st term, r= common ratio and n, the rank
In the formula given a₁ = 5, r = 3/2 and n = 6 (we have to find the 6th term value).
a₆ = 5.(3/2)⁶⁻¹ = 5.(3/2)⁵ = 1215/32 (answer C)
Answer:
W = 2.5d + 62
Step-by-step explanation:
The calf weighed 62 pounds when they were born. This gives us a base of 62 pounds - the calf cannot weigh less than 62 pounds and it does on day 0. On each day , the calf gains 2.5 pounds. We can times the number to days by 2.5 to get the gain from day 0. We can add these two values together to get the total current weight of the calf.
Answer:
Yes
Step-by-step explanation:
There is no unclosable gap. 7+1>7. 7+7>1. An isosceles triangle would be formed.
To solve this, you need to isolate/get the variable "c" by itself in the equation:
4c + 8c = -55 + 3c You can first combine like terms (4c and 8c)
12c = -55 + 3c Subtract 3c on both sides
9c = -55 Divide 9 on both sides
Rigid mapping is used to illustrate rigid transformation.
The rigid mapping rules are:
- <em>(a) (x, y)->(y,x)
</em>
- <em>(c) (x, y)->(-y, x)
</em>
- <em>(d) (x, y)-> (-y +4, X-6)
</em>
- <em>(e) (x, y)->(x + 4, y-5)
</em>
- <em>(f) (x, y)->(x, x+y)
</em>
<em />
All transformations are rigid except dilation.
This is so, because dilation <em>changes the size </em>of the function that is being transformed, while others do not.
Dilations are represented by scale factors (<em>product or division</em>)
From the list of given options
<em>(b) (x, y)->(3x, y) and (c) (x,y)-> (3)</em> are non-rigid mapping because they represent dilations.
Hence, the rigid mapping rules are:
- <em>(a) (x, y)->(y,x)
</em>
- <em>(c) (x, y)->(-y, x)
</em>
- <em>(d) (x, y)-> (-y +4, X-6)
</em>
- <em>(e) (x, y)->(x + 4, y-5)
</em>
- <em>(f) (x, y)->(x, x+y)
</em>
<em />
Read more about transformation at:
brainly.com/question/13801312
