In slope intercept form this is equal to y=3/2x+8. If you want it in decimal form it would be y=1.5x+8.
Answer:
Domain) all x
Range) 1
Step-by-step explanation:
The domain is the x values and the range is the y values
In this case anything could be x, and y can only be 1
Answer:
2/5
Step-by-step explanation:
did the test
Answer:
No Solution
Step-by-step explanation:
12x + 3 = 72x + 5
subtract 12x from both sides
end up with
3 = 72x - 12x + 5
subtract 12x to 72x
3 = 60x + 5
-5 from both sides
-8 = 60x
since x is a bigger number the answer would be NO SOLUTION
12x + 3 = 72x + 5
I do not understand lins logic
x + 6 = 7x + 10
subtract 6 from both sides
x = 7x + 4
move 7x to the other side
7x = 4
divide 7
x = 0.5
Also wrong because I get how lin got that answer
My way
12x + 3 = 72x + 5
-12 x from both sides
3 = 60x + 5
+5 to other side
8 = 60x
if the x was on the other side it would make sense
but it is not so the Answer is NO SOLUTION
Hope this Helped :)
The true statement about the graph of the function f(x) = x3 - 2x2 + 4x – 8 is (B) The function has 1 real zero that occurs 1 time.
<h3>How to determine the true statement</h3>
The function of f(x) is represented as:

Differentiate the function f(x)

Calculate the minimum value using:

So, we have:


Substitute 2/3 in f'(x)


The value of f'(2/3) is greater than 0.
This means that the function f(x) has 1 real zero, and it occurs once at point (2,0)
Hence, the true statement is (b)
Read more about functions at:
brainly.com/question/13136492