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AnnZ [28]
4 years ago
14

Find C to form completing Square

{2} +5x + C" alt="x^{2} +5x + C" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
postnew [5]4 years ago
3 0

Answer:

\frac{25}{4}  (or 6.25)

Step-by-step explanation:

Let's do a simple square problem to see the relationship between the elements of the resulting equation...

(x+3)(x+3) = x(x+3) + 3(x+3) = x^{2} +3x + 3x + 9 = x^{2} + 6x + 9

As you see, the number of 'x' (6) is the double of the numeric part of the binomial expression (3), while the numeric-only part (9) is the square of the numeric part of the binomial expression (3).

So, if we look at the formula from the problem, we see the the number of 'x' is 5. To obtain the C value, we need to divide the 5 by 2... then get the square value of the result.

\frac{5}{2} * \frac{5}{2} = \frac{25}{4}  (or 6.25)

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What is 12.462 rounded to ones
AnnZ [28]
Hey There!

12.462 rounded to ones is 12. :)

Thank You!

Questions, comments, or concerns? Feel free to PM me!



4 0
3 years ago
Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the corre
Snowcat [4.5K]

Answer:

1. 8x

2. 2x squared

3. 6xy

4. 5y

Step-by-step explanation:

Trust me :)

7 0
3 years ago
I need help with number 5 please
steposvetlana [31]

Answer: Would be 55% I hope this helps!

7 0
3 years ago
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Greata had a price of cloth that is 9 yards long. She cuts it into prices that are each 1/3 yard long. How many prices of cloth
KonstantinChe [14]

Given:

Length of cloth = 9 yards

Length of pieces = \dfrac{1}{3} yards each

To find:

The number of pieces of cloths after cutting.

Solution:

Let n be the number of required pieces.

Length of each piece is \dfrac{1}{3} yards. So, the length of n pieces is \dfrac{1}{3}n yards.

The length of the whole cloth is 9 yards. So, \dfrac{1}{3}n yards must be equal to 9 yards.

\dfrac{1}{3}n=9

Multiply both sides by 3.

n=9\times 3

n=27

Therefore, the Greata have 27 pieces of cloths.

5 0
3 years ago
Question 11 of 25
Olegator [25]

\\ \sf\longmapsto x+4=\sqrt{8-x}

\\ \sf\longmapsto (x+4)^2=8-x

\\ \sf\longmapsto x^2+16+8x=8-x

\\ \sf\longmapsto x^2+8x-x+16-8=0

\\ \sf\longmapsto x^2+7x+8=0

\\ \sf\longmapsto x^2-8x+x+8

\\ \sf\longmapsto (x-8)(x-1)=0

\\ \sf\longmapsto x=8,-1

Option C

4 0
3 years ago
Read 2 more answers
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