1597 <span>89 </span> = 17.9438202247
17.9438202247 = 179.438202247 to the nearest tenth
17.9438202247 = 17.94 to the nearest hundredth
17.9438202247 = 17.944 to the nearest thousandth
= 0 to the nearest tenth
= 0 to the nearest hundredth
= 0 to the nearest thousandth
Other Divisions Math homework are
1597 divide by half plus 20
Answer:
Cost function C(x) == FC + VC*Q
Revenue function R(x) = Px * Q
Profit function P(x) =(Px * Q)-(FC + VC*Q)
P(12000) = -38000 Loss
P(23000) = 28000 profit
Step-by-step explanation:
Total Cost is Fixed cost plus Variable cost multiplied by the produce quantity.
(a)Cost function
C(x) = FC + vc*Q
Where
FC=Fixed cost
VC=Variable cost
Q=produce quantity
(b)
Revenue function
R(x) = Px * Q
Where
Px= Sales Price
Q=produce quantity
(c) Profit function
Profit = Revenue- Total cost
P(x) =(Px * Q)-(FC + vc*Q)
(d) We have to replace in the profit function
<u>at 12,000 units </u>
P(12000) =($20 * 12,000)-($110,000 + $14*12,000)
P(12000) = -38000
<u>at 23,000 units </u>
P(x) =($20 * 23,000)-($110,000 + $14*23,000)
P(23000) = 28000
Answer:
Step-by-step explanation:
y=-1/3x+9
This is written in the format y=mx+b, where m is the slope and b the y-intercept (the value of y when x=0).
Perpendicular lines have a slope that is the negative inverse of the slope of the reference line, in this case -(1/3). The new slope is 3. equation is:
y = 3x + b
To find b, enter the given point, (-6,-2) and solve for b:
y = 3x + b
-2 = 3(-6) + b
-2 = -18 + b
b = 16
The full equation is y=3x + 18
Answer:
Step-by-step explanation:
Given that a bag contains 40 cards numbered 1 through 40 that are either red or blue. A card is drawn at random and placed back in the bag.
This is done four times. Two red cards are drawn, numbered 31 and 19, and two blue cards are drawn, numbered 22 and 7.
From the above we cannot conclude that red cards and even numbers are mutually exclusive
Just drawing two red cards and because the two happen to be odd we cannot generalize the red cards have odd numbers.
This might have occurred due to simple chance from a comparatively large number of 40 cards.
Suppose say we have red cards 20, and 19 red 1 blue.
Then drawing 2 from 19 red cards have more probability and this can occur by chance.
So friend's conclusion is wrong.
