Answer:
Option (e).
Explanation:
Meiosis may be defined as the process of cell division in which a single parent cell divides into four daughter cells. The chromosome number reduces to half in meiosis.
Crossing over is the process of exchange of genetic material between the homologous chromosomes of the non-sister chromatids. Crossing over will bring variation in the gametes. Hence, the absence of crossing over results in the formation of gametes with less genetic variation.
Thus, the correct answer is option (e).
The answer is Glycolysis. Glycolysis is the first stage of Respiration that happens in the cytoplasm of the cell. In this process, a 6-carbon sugar molecules is broken down to form 2 molecules of 3-carbon pyruvate. The process of Glycolysis generates ATP in the presence of oxygen.
Answer:
1/3 of black F2 progeny will be homozygous.
Explanation:
Here, BB = black coat color = true breeding dominant black strain
bb = white coat color = true breeding recessive white strain
When true breeding black and white guinea pigs are mated to give F1 progeny:
BB X bb = Bb ( all black guinea pigs )
When two of the F1 guinea pigs are mated to give F2 progeny:
Bb X Bb = BB, Bb, Bb, bb
F2 progeny has 3/4 progeny as black (BB and Bb) . Out of them 1/3 are homozygous and 2/3 are heterozygous.
Hence, 1/3 of black F2 progeny will be homozygous.
The right answer is reticulocyte.
The reticulocyte is the cell preceding the erythrocyte stage in erythropoiesis. He is almost like her.
Reticulocytes are young red blood cells that still have ribosomes and mitochondria, but no peroxisomes. They are therefore capable of a fairly intense metabolism and they still actively synthesize hemoglobin.
Viruses cannot reproduce. they instead copy themselves with the help of a host cell. a cell can reproduce and doesn’t need help from other cells
