Answer:
Nevermind. I figured it out!
=oh!!(^__^)
Answer:
Tropical climates are wet and warm, while dry climates receive little or no rain. 3. ... Earth's five major climate zones are identified by temperature, precipitation, and plant life.
Answer:
The correct statements are options C, E and F.
Explanation:
The SDS-PAGE refers to a broadly utilized technique for distinguishing proteins. The SDS or the sodium dodecyl sulfate refers to an ionic detergent. The SDS-protein complexes possess negative charge with identical charge to mass ratio such that when the proteins are run on the gel they are distinguished on the basis of their size.
As the SDS entices a negative charge to the proteins, the migration of the proteins takes place towards the positive electrode. The migration of protein takes place on the basis of the size. Thus, smaller proteins seem to migrate quickly via the gel in comparison to the bigger proteins. The binding of the protein takes place with about 1.4 times its mass of SDS resulting in the formation of a large overall negative charge.
Answer:
Green, red or orange
Explanation:
Benedict's solution is used to test for simple sugars, such as glucose. It is a clear blue solution of sodium and copper salts. A potion of sugar solution is added an equal amount of benedict's solution and heated to boil. In the presence of simple sugars, the blue solution changes color from blue to green, yellow, and red, depending on the amount of sugar. When the solution turns to orange, it indicates that there is presence of reducing sugars.
Answer:
See the answer below
Explanation:
Recall that: <em>Water potential = pressure potential + solute potential</em>
Since the system is an open one;
<em>Water potential = solute potential = -iCRT</em>
i = number of particles the molecle will make in water (1)
C = molar concentration
R = Pressure constant = 0.0831 liter bar/mole K
T = temperature in kelvin = 22 + 273 = 295 K
To calculate water potential on side A:
C = 1 M
Water potential = - (1 x 1 x 0.0831 x 295) = -24.51 bars
For side B:
C = 2 M
Water potential = - (1 x 2 x 0.0831 x 295) = -49.03 bars
b.
<em>Since side A has higher water potential than side B, water will flow from side A to side B until equilibrium is established between the two sides. Water always flows from the region of higher water potential to the region of lower water potential.</em>
<em />