“The breaking distance is directly proportional to the square of its speed”
Using your variables, this means: d = k•b^2
k here is some unknown (and for this question irrelevant) number.
Now if b (the speed) is increased by 200%, then your new speed is b+2b = 3b. The 2b is the 200% increase.
Throw 3b into the first equation we have the new d as:
d = k • (3b)^2
Simplifying this, you have d = k•9b or d=9kb
This means the new braking distance is 9 times the original braking distance.
Answer:
the answer is K . the product of 51 and 999 is 50949 and 5 is greater than 0.
Answer:
output = n + 2
Step-by-step explanation:
from the table of input/ output values
2 → 4 is 2 + 2 = 4
5 → 7 is 5 + 2 = 7
9 → 11 is 9 + 2 = 11
Thus to obtain the output add 2 to the input
When input is n then output is n + 2
Answer:
this question doed not make sense
Step-by-step explanation:
