H=9;8)B=(5;4) (ball)R=(7;0) (hit point)B'=symetric of B axis perpendicular of x in RB'=(7+(7-5);4)=(9;4)Equation BR: y-4=(0-4)/(7-5)(x-5)==>y=-2x+14Equation RB': y-4=(4-0)/(9-7)(x-9)==>y=2x-14
Is H a point of RB'? y=2x-14 : 8=? 2*9-14==>8=?4
no, you will not make your putt.
I hope this helps you and have a great day!! :)
Answer:

Step-by-step explanation:
Every inscribed right triangle has its hypotenuse as the same size of the Diameter. Assuming that, this is the case check the picture below.
So the hypotenuse= D=2R=12
- Shaded Area = Area of the Circle- Area of the Triangle

Finding the Triangle base via the Pythagorean Theorem

Now plugging in the base of the triangle on that formula:

Finally,
Shaded Area =
Parallel I think is the right answer
Answer:
Infinite solutions
Step-by-step explanation:
3*x is 3x and 3*3 is 9
I used foil to make the equations look equal to each other.
since they're both equal to y you can set them equal to each other also.
3x+9=3(x+3)
3x+9=3x+9
bruh
Answer:
1 is in the unit place and 7 is in the tenths place and the fraction for this is 1 and 7/10 the one is a whole number and the seven tenths is a fraction and thats your answer