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Butoxors [25]
3 years ago
9

What is the fraction form of the following decimal expansion? 1.7 continued

Mathematics
2 answers:
kramer3 years ago
7 0

Answer:

1 is in the unit place and 7 is in the tenths place and the fraction for this is 1 and 7/10 the one is a whole number and the seven tenths is a fraction and thats your answer

Step-by-step explanation:

allsm [11]3 years ago
4 0

Answer:

1 is in the unit place and 7 is in the tenths place and the fraction for this is 1 and 7/10 the one is a whole number and the seven tenths is a fraction and thats your answer

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You put $800 in an account that earns 4% simple interest. Find the total amount in your account after each year for 3 years. (Pl
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To get 4% of 800 you times 800 by 4 and divide it by 100. Once you have that amount you add it to 800 to find the amount you will have in your bank the first year. To get the next year's amount you then get 4% of 832(because after the first year you have more than $800) and then add the 4% to 832, that is the answer for the second year. To find the third year's amount you get 4% of the new amount (last year's total) and add it to last year's total, that is your total for the third year. So the first year will be: (800x4÷100)+800 =32+800 =832 The second year will be: 832+(832x4÷100) =832+33.28 =865.28 The third year will be: (865.28×4÷100)+865.28 =34.61(rounded off)+865.28 =899.89
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What is the surface area of a sphere with the radius of 3?
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In triangle KLM, if K is congruent to L, KL = 9x - 40, LM = 7x - 37, & KM = 3x + 23, find x & the measure of each angle.
Dennis_Churaev [7]

Answer: x = 15, ∠K = 45.7°, ∠L = 45.7°, ∠M = 88.6°

<u>Step-by-step explanation:</u>

Since ∠K ≅ ∠L, then ΔKLM is an isoceles triangle with base KL

 KM ≅ LM

3x + 23 = 7x - 37

       23 = 4x - 37

       60 = 4x

        15 = x

KM = LM = 3x + 23

               = 3(15) + 23

               = 45 + 23

               = 68

KL = 9x - 40

    = 9(15) - 40

    = 135 - 40

    = 95

Next, draw a perpendicular bisector KN from K to KL. Thus, N is the midpoint of KL and ΔMNL is a right triangle.

  • Since N is the midpoint of KL and KL = 95, then NL = 47.5
  • Since ∠N is 90°, then NL is adjacent to ∠l and ML is the hypotenuse

Use trig to solve for ∠L (which equals ∠K):

cos ∠L = \frac{adjacent}{hypotenuse}

cos ∠L = \frac{47.5}{68}

      ∠L = cos⁻¹ (\frac{47.5}{68})

      ∠L = 45.7  

Triangle sum Theorem:

∠K + ∠L + ∠M = 180°    

45.7 + 45.7 + ∠M = 180

       91.4     + ∠M = 180

                      ∠M = 88.6

       

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3 years ago
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