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Connor took out a 4 year loan to buy a car at a 4% simple interest rate. if he has to pay $240 in interest, how much principal d

uysha [10]

Answer:

The principal borrow for loan is $1,500 .

Step-by-step explanation:

Given as :

The interest paid on simple interest = s.i = $240

The rate of simple interest applied = r = 4%

The time period for loan = t = 4 years

Let The principal borrow = $p

Now,<u> from Simple Interest method</u>

Simple Interest = $\dfrac{\textrm principal\times \textrm rate\times \textrm time}{100}$

Or. s.i = $\dfrac{\textrm p\times \textrm r\times \textrm t}{100}$

Or, $240 = $\dfrac{\textrm p\times \textrm 4\times \textrm 4}{100}$

Or, $240 × 100 = 16 × p

Or, $24000 = 16 × p

∴ p = $\dfrac{24000}{16}$

i.e p = $1,500

So, The principal borrow for loan = p = $1,500

Hence, The principal borrow for loan is $1,500 . Answer

3 0

3 years ago

A rectangle is 12m longer than it is wide. Its perimeter is 68m. Find its length and width?

Juliette [100K]

The width is 11m and the length is 23m

5 0

3 years ago

Determine the domain and range of the graph.

nirvana33 [79]

Answer:

Domain [-4,4]

Range [-2,2]

Step-by-step explanation:

The domain is the x-values of the graph and the range in the y-values. When writing domain and range it should be from least to greatest. So to find the domain find the lowest x-value on the graph and then the highest. Next, do the same for y-values. Finally, either surround each value with parentheses or bracket, the difference is that brackets mean that value is included, while parentheses mean that value is not actually on the graph.

In this case, the lowest x-value is -4 and the highest is 4, both values are included as signified by the closed circles, therefore the domain is [-4,4]. The lowest y value is -2 and the highest is 2, both are included, therefore the range is [-2,2].

4 0

3 years ago

What is x. Please show *all* the steps.

Zolol [24]

The equation 5/2 - x + x - 5/x + 2 + 3x + 8/x^2 - 4 = 0 is a quadratic equation

The value of x is 8 or 1

<h3>How to determine the value of x?</h3>

The equation is given as:

5/2 - x + x - 5/x + 2 + 3x + 8/x^2 - 4 = 0

Rewrite as:

-5/x - 2 + x - 5/x + 2 + 3x + 8/x^2 - 4 = 0

Take the LCM

[-5(x + 2) + (x -5)(x- 2)]\[x^2 - 4 + [3x + 8]/[x^2 - 4] = 0

Expand

[-5x - 10 + x^2 - 7x + 10]/[x^2 - 4] + [3x + 8]/[x^2 - 4] = 0

Evaluate the like terms

[x^2 - 12x]/[x^2 - 4] + [3x + 8]/[x^2 - 4 = 0

Multiply through by x^2 - 4

x^2 - 12x+ 3x + 8 = 0

Evaluate the like terms

x^2 -9x + 8 = 0

Expand

x^2 -x - 8x + 8 = 0

Factorize

x(x -1) - 8(x - 1) = 0

Factor out x - 1

(x -8)(x - 1) = 0

Solve for x

x = 8 or x = 1

Hence, the value of x is 8 or 1