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2 years ago

∠A and \angle B∠B are complementary angles. If m\angle A=(x+13)^{\circ}∠A=(x+13)

Mathematics

1 answer:

slavikrds [6]2 years ago

5 0

Answ

$x^{2} \pi \alpha \frac{x}{y}$

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what will be the total paid on an amortized loan of $15,000 for 5 years at 2 3/4% compounded monthly?

Alex73 [517]

the loan is being amortized, so that doesn't matter for its future value, the simple case that the borrower is paying it in bits monthly.

so, we're really just looking for the future value of the Principal $15000, let's convert theat mixed fraction to improper fraction, and then to a percent format firstly.

$\bf \stackrel{mixed}{2\frac{3}{4}}\implies \cfrac{2\cdot 4+3}{4}\implies \stackrel{improper}{\cfrac{11}{4}}\implies \stackrel{decimal}{2.75} \\\\[-0.35em] ~\dotfill\\\\ ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt}$

$\bf \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$15000\\ r=rate\to 2.75\%\to \frac{2.75}{100}\dotfill &0.0275\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{monthly, thus twelve} \end{array}\dotfill &12\\ t=years\dotfill &5 \end{cases} \\\\\\ A=15000\left(1+\frac{0.0275}{12}\right)^{12\cdot 5}\implies A=15000\left( \frac{4811}{4800} \right)^{60}\implies A\approx 17208.318305$

how did we get 4811/4800? well, is really just the 1+(0.0275/12), which gives us about 1.0022917 but is a repeating decimal, so 4811/4800 is just the fraction version of it.

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3 years ago

6 music CDs to 8 DVDs, 18 music CDs to 24 DVDs. Determine whether the ratios are equivalent. Show your work

atroni [7]

They are indeed equivalent.
The ratios can be set up as 6/8 and 18/24.
Once simplified, both of these ratios become 3/4, and are therefore equivalent.

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3 years ago

Draw a picture to show how to find12+37

Karolina [17]

So i drew 12 circles and 37 circles
And i got 49 total:D
i hope this helps and sorry that the pic is wierd:(

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4 years ago

What is the domain of the function

IRINA_888 [86]

$\sqrt{5+x}$ is defined as long as $5+x\ge0$ , or $x\ge-5$ . However, $\dfrac1x$ is undefined when $x=0$ . This point is contained in the set $\{x|x\ge-5\}$ , so we need to exclude it. We can write the domain in several ways.

$\{x|x\ge-5~\land~x\neq0\}$
$-5\le x$
$[-5,0)\cup(0,\infty)$

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3 years ago

Y= (0. (1, (2, (3. (4, (5,

skad [1K]

Answer:

y = (0, 1, 32, 243, 1024, 3125)

3 0

3 years ago