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torisob [31]
2 years ago
8

In Euclidean geometry, a line continues in opposite directions forever. As a result_

Mathematics
1 answer:
viva [34]2 years ago
3 0

Euclidean geometry differs from spherical geometry because Euclidean Geometry are known to make use of a plane to be able to set points and lines, but Spherical Geometry are known to make use of spheres to set up points and great circles.

Note also that in spherical geometry, angles are said to be defined between great circles.

<h3>How does Euclidean geometry differ from other type of geometry?</h3>

Euclidean geometry is one that seeks to know more the geometry of flat, as well as two-dimensional spaces. But non-Euclidean geometry are known to often studies curved, instead of flat, surfaces.

Therefore, Euclidean geometry differs from spherical geometry because Euclidean Geometry are known to make use of a plane to be able to set points and lines, but Spherical Geometry are known to make use of spheres to set up points and great circles.

Learn more about Euclidean Geometry from

brainly.com/question/2251564

#SPJ1

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240 calories

Step-by-step explanation

You're doubling the amount of fudge, so double the amount of calories. You could also think of it as 2 4-oz portions of fudge, then just add the calories (120+120) together.

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Higher order thinking: Jeff finds some bugs. He finds 10 Fewer grasshoppers than crickets. He finds 5 fewer crickets than Lady b
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I need help with this question please and thank you
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13 cups

Step-by-step explanation:

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Eli has saved $8 more than 1/3 of Angela’s savings.If they each save $10 more Eli will have saved &amp;4 more than Angela’s savi
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4 years ago
At an ocean-side nuclear power plant, seawater is used as part of the cooling system. This raises the temperature of the water t
grandymaker [24]

Answer:

(a1) The probability that temperature increase will be less than 20°C is 0.667.

(a2) The probability that temperature increase will be between 20°C and 22°C is 0.133.

(b) The probability that at any point of time the temperature increase is potentially dangerous is 0.467.

(c) The expected value of the temperature increase is 17.5°C.

Step-by-step explanation:

Let <em>X</em> = temperature increase.

The random variable <em>X</em> follows a continuous Uniform distribution, distributed over the range [10°C, 25°C].

The probability density function of <em>X</em> is:

f(X)=\left \{ {{\frac{1}{25-10}=\frac{1}{15};\ x\in [10, 25]} \atop {0;\ otherwise}} \right.

(a1)

Compute the probability that temperature increase will be less than 20°C as follows:

P(X

Thus, the probability that temperature increase will be less than 20°C is 0.667.

(a2)

Compute the probability that temperature increase will be between 20°C and 22°C as follows:

P(20

Thus, the probability that temperature increase will be between 20°C and 22°C is 0.133.

(b)

Compute the probability that at any point of time the temperature increase is potentially dangerous as follows:

P(X>18)=\int\limits^{25}_{18}{\frac{1}{15}}\, dx\\=\frac{1}{15}\int\limits^{25}_{18}{dx}\,\\=\frac{1}{15}[x]^{25}_{18}=\frac{1}{15}[25-18]=\frac{7}{15}\\=0.467

Thus, the probability that at any point of time the temperature increase is potentially dangerous is 0.467.

(c)

Compute the expected value of the uniform random variable <em>X</em> as follows:

E(X)=\frac{1}{2}[10+25]=\frac{35}{2}=17.5

Thus, the expected value of the temperature increase is 17.5°C.

7 0
4 years ago
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