Answer: For this, you have to calculate the Unit value,
Unit value of 1rst one, 4.99/6 = 0.83
Unit value of 2nd one, 7.99/10 = 0.79
As, 2nd one is cheaper, so it is better :))
Step-by-step explanation:
Answer:
bruh
Step-by-step explanation:
fpkgjdfgjd
Answer:
Step-by-step explanation:
a.
£100
1:3
1+3=4
1/4×£100
=£25
3/4×£100
=£75
b.
£80
3:5
3+5=8
3/8×£80
=£30
5/8×£80
=£50
C.
£250
2:3:5
2+3+5=10
2/10×£250
=£50
3/10×£250
=£75
5/10×£250
=£125
Answer:
Final answer is ![\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=x](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E1%7D%5Ccdot%5Csqrt%5B3%5D%7Bx%5E2%7D%3Dx)
.
Step-by-step explanation:
Given problem is ![\sqrt[3]{x}\cdot\sqrt[3]{x^2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%7D%5Ccdot%5Csqrt%5B3%5D%7Bx%5E2%7D)
.
Now we need to simplify this problem.
![\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E1%7D%5Ccdot%5Csqrt%5B3%5D%7Bx%5E2%7D)
Apply formula
![\sqrt[n]{x^p}\cdot\sqrt[n]{x^q}=\sqrt[n]{x^{p+q}}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bx%5Ep%7D%5Ccdot%5Csqrt%5Bn%5D%7Bx%5Eq%7D%3D%5Csqrt%5Bn%5D%7Bx%5E%7Bp%2Bq%7D%7D)
so we get:
![\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=\sqrt[3]{x^{1+2}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E1%7D%5Ccdot%5Csqrt%5B3%5D%7Bx%5E2%7D%3D%5Csqrt%5B3%5D%7Bx%5E%7B1%2B2%7D%7D)
![\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=\sqrt[3]{x^{3}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E1%7D%5Ccdot%5Csqrt%5B3%5D%7Bx%5E2%7D%3D%5Csqrt%5B3%5D%7Bx%5E%7B3%7D%7D)
Hence final answer is .
Answer:
No Solution.
Step-by-step explanation:
2(x-1)-y=-8
y=2x+8
----------------
2x-2-(2x+8)=-8
2x-2-2x-8=-8
2x-2x-2-8=-8
0-2-8=-8
-2-8=-8
-10=-8
no solution
