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3 years ago

What is the value of the expression |a + b| + |c| when a = –3, b = 7, and c = 1

Mathematics

2 answers:

amid [387]3 years ago

8 0

Answer:

Step-by-step explanation:

abs(a + b) + abs(c)

abs(-3 + 7) + abs(1)

abs(4) + abs(1)

4 + 1

Damm [24]3 years ago

6 0

The answer is 5 hope this helps

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Viefleur [7K]

Answer:

41*

Step-by-step explanation:

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Hope This Helps;)<3

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2 years ago

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the diameter of your bicycle wheel is 34 inches.What is its radius?How far will you move in one turn if your wheel?What is the d

gulaghasi [49]

Answer:

Step-by-step explanation:

The radius of a circle is always half the radius.

Thus, in this case, the radius is (1/2)(34 in) = 17 in.

The "how far" question is answerable by finding the circumference of the wheel. The circumference, C, is found by calculating C = πd, where d is the diameter of the circle in question.

Here, C = (34 in)π, which comes out to 106.81 inches. The bike will move 106.81 inches forward if the wheel turns once.

If the wheel turns 5 times, the total distance traveled is 5 times the circumference, or 5(106.81 in) = 534.07 in.

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3 years ago

Can someone help pls

svet-max [94.6K]

Answer: y-4=0

Step-by-step explanation:

7 0

3 years ago

Is PB>PY? yes or no

Nadusha1986 [10]

Answer:

yes

Step-by-step explanation:

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3 years ago

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How do i solve that question?

yawa3891 [41]

a) The solution of this ordinary differential equation is $y =\sqrt[3]{-\frac{2}{\frac{3\cdot t}{8}-\frac{\sin 2t}{4}+\frac{\sin 4t}{32}-2 } }$ .

b) The integrating factor for the ordinary differential equation is $-\frac{1}{x}$ .

The particular solution of the ordinary differential equation is $y = \frac{x^{3}}{2}+x^{2}-\frac{5}{2}$ .

<h3>How to solve ordinary differential equations</h3>

a) In this case we need to separate each variable ( $y, t$ ) in each side of the identity:

$6\cdot \frac{dy}{dt} = y^{4}\cdot \sin^{4} t$ (1)

$6\int {\frac{dy}{y^{4}} } = \int {\sin^{4}t} \, dt + C$

Where $C$ is the integration constant.

By table of integrals we find the solution for each integral:

$-\frac{2}{y^{3}} = \frac{3\cdot t}{8}-\frac{\sin 2t}{4}+\frac{\sin 4t}{32} + C$

If we know that $x = 0$ and $y = 1$ , then the integration constant is $C = -2$ .

The solution of this ordinary differential equation is $y =\sqrt[3]{-\frac{2}{\frac{3\cdot t}{8}-\frac{\sin 2t}{4}+\frac{\sin 4t}{32}-2 } }$ . $\blacksquare$

b) In this case we need to solve a first order ordinary differential equation of the following form:

$\frac{dy}{dx} + p(x) \cdot y = q(x)$ (2)

Where:

$p(x)$ - Integrating factor
$q(x)$ - Particular function

Hence, the ordinary differential equation is equivalent to this form:

$\frac{dy}{dx} -\frac{1}{x}\cdot y = x^{2}+\frac{1}{x}$ (3)

The integrating factor for the ordinary differential equation is $-\frac{1}{x}$ . $\blacksquare$

The solution for (2) is presented below:

$y = e^{-\int {p(x)} \, dx }\cdot \int {e^{\int {p(x)} \, dx }}\cdot q(x) \, dx + C$ (4)

Where $C$ is the integration constant.

If we know that $p(x) = -\frac{1}{x}$ and $q(x) = x^{2} + \frac{1}{x}$ , then the solution of the ordinary differential equation is:

$y = x \int {x^{-1}\cdot \left(x^{2}+\frac{1}{x} \right)} \, dx + C$

$y = x\int {x} \, dx + x\int\, dx + C$

$y = \frac{x^{3}}{2}+x^{2}+C$

If we know that $x = 1$ and $y = -1$ , then the particular solution is:

$y = \frac{x^{3}}{2}+x^{2}-\frac{5}{2}$

The particular solution of the ordinary differential equation is $y = \frac{x^{3}}{2}+x^{2}-\frac{5}{2}$ . $\blacksquare$

To learn more on ordinary differential equations, we kindly invite to check this verified question: brainly.com/question/25731911

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2 years ago