Answer:
TC (A) = 40x , TC (B) = 500 + 20x
Step-by-step explanation:
Let the number of students be = x
Hall A Total Cost
Relationship Equation, where TC (A) = f (students) = f (x) 40 per person (student) = 40x
Hall B Total Cost
Relationship Equation, where TC (B) = f (students) = f (x) 500 fix fee & 20 per person (student) = 500 + 20x
Answer:
28
Step-by-step explanation:
Jane spent $42 for shoes. This was $14 less than twice what she spent for a blouse . How much was the blouse?
Next, identify the numbers.
Jane spent $42 for shoes. This was $14 less than twice what she spent for a blouse . How much was the blouse?
Next, identify the key words. These include add, subtract, remove, spend, earn, less, more, times, twice, half, etc.
Jane spent $42 for shoes. This was $14 less than twice what she spent for a blouse . How much was the blouse?
Finally, convert everything into an equation.
42
=
2
⋅
blouse
−
14
Now, solve the equation.
56
=
2
⋅
b
l
o
u
s
e
b
l
o
u
s
e
=
28
X = 50 (Is parallel to the y-axis so there is no intersection point)
Y= 40 (Is parallel to the x-axis so there is no intersection point)
Both no intercept with the other
Answer:
The value of b is, 8
Step-by-step explanation:
To determine the value of b:
Given:
....[1]
Since, 0x6A represents the hexadecimal form.
To convert this hexadecimal form into decimal form:
⇒
(decimal form)
Now we have to convert this decimal form into octal
8 | 106
8 | 13 | 2
| 1 | 5
1
Then, the octal form we get, 
Substitute this in [1] we have;
On comparing both sides we have;
b = 8
Therefore, the value of b is, 8
Multiply the two brackets together
(2x-1)(x-2)
2x(x)(2x*-2)(-1*x)(-1*-2)
2x^2-4x-x+2
2x^2-5x+2
Answer is 2x^2-5x+2 - J
