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3 years ago

8

The area of a rectangular city park is 24/54 square miles. The length of the park is 5/9 mile. What is the width, in miles,of th

e park.Show your work

1 answer:

VikaD [51]3 years ago

3 0

I hope this helps you

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A certain number is the same as the square root of the product of 8 and the number find the number

Rudik [331]

So, we have x=√8x. The square root is a number times itself, so x=√x*x. That means that 8 is x.

6 0

4 years ago

What is the slope of the line that passes through the points (1, 1) and (4, 4)?

gizmo_the_mogwai [7]

Answer:

The answer is 1

Step-by-step explanation:

Formula for finding the slope: $\frac{y2-y1}{x2-x1}$

Take y2 and y1 from (4,<u>4</u>) (1,<u>1</u>)

Take x2 and x1 from (<u>4</u>,4) (<u>1</u>,1)

$\frac{y2-y1}{x2-x1} = \frac{4-1}{4-1} = \frac{3}{3} = 1$

This is how the answer is 1

Hope it helps :)

8 0

2 years ago

Verify identity: <br><br> (sec(x)-csc(x))/(sec(x)+csc(x))=(tan(x)-1)/(tan(x)+1)

Nikitich [7]

So hmmm let's do the left-hand-side first

$\bf \cfrac{sec(x)-csc(x)}{sec(x)+csc(x)}\implies \cfrac{\frac{1}{cos(x)}-\frac{1}{sin(x)}}{\frac{1}{cos(x)}+\frac{1}{sin(x)}}\implies 
\cfrac{\frac{sin(x)-cos(x)}{cos(x)sin(x)}}{\frac{sin(x)+cos(x)}{cos(x)sin(x)}}
\\\\\\
\cfrac{sin(x)-cos(x)}{cos(x)sin(x)}\cdot \cfrac{cos(x)sin(x)}{sin(x)+cos(x)}\implies \boxed{\cfrac{sin(x)-cos(x)}{sin(x)+cos(x)}}$

now, let's do the right-hand-side then

$\bf \cfrac{tan(x)-1}{tan(x)+1}\implies \cfrac{\frac{sin(x)}{cos(x)}-1}{\frac{sin(x)}{cos(x)}+1}\implies \cfrac{\frac{sin(x)-cos(x)}{cos(x)}}{\frac{sin(x)+cos(x)}{cos(x)}}
\\\\\\
\cfrac{sin(x)-cos(x)}{cos(x)}\cdot \cfrac{cos(x)}{sin(x)+cos(x)}\implies \boxed{\cfrac{sin(x)-cos(x)}{sin(x)+cos(x)}}$

7 0

3 years ago

A rectangular Corn Hole area at the Recreation Center has a width of 5 feet and a length of 10 feet. If

lbvjy [14]

Answer:

2ft

Step-by-step explanation:

5 x 10=50

7 x 12= 84

5+2=7 and 10+2=12

3 0

3 years ago

On a particular production line,the likelihood that a light bulb is defective is 5%. Ten light bulbs are randomly selected. What

KengaRu [80]

Answer:

Mean and Variance of the number of defective bulbs are 0.5 and 0.475 respectively.

Step-by-step explanation:

Consider the provided information,

Let X is the number of defective bulbs.

Ten light bulbs are randomly selected.

The likelihood that a light bulb is defective is 5%.

Therefore sample size is = n = 10

Probability of a defective bulb = p = 0.05.

Therefore, q = 1 - p = 1 - 0.05 = 0.95

Mean of binomial random variable: $\mu=np$

Therefore, $\mu=10(0.05)=0.5$

Variance of binomial random variable: $\sigma^2=npq$

Therefore, $\sigma^2=10(0.05)(0.95)=0.475$

Mean and Variance of the number of defective bulbs are 0.5 and 0.475 respectively.

5 0

3 years ago