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horrorfan [7]
1 year ago
14

FIND X IF AB=X+12, BC = x + 12₁ And AC = 14

Mathematics
1 answer:
MissTica1 year ago
3 0

Given that B is a point between point A and C, the numerical value of x is -5.

<h3>What is the numerical value of x?</h3>

An equation is simply a mathematical formula that expresses the equality of two expressions, using the equals sign as a connection between them.

Given the data in the question;

  • B is a point between point A and C
  • Segment AC = 14
  • Segment AB = x + 12
  • Segment BC = x + 12
  • Numerical value of x = ?

Since B is a point between point A and C.

Segment AC = Segment AB + Segment BC

Plug in the given values and solve for the value of x

Segment AC = Segment AB + Segment BC

14 = (x + 12) + (x + 12)

14 = x + 12 + x + 12

14 = 2x + 24

2x = 14 - 24

2x = -10

x = -10/2

x = -5

Given that B is a point between point A and C, the numerical value of x is -5.

Learn more about equations here: brainly.com/question/9236233

#SPJ1

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Simplify 4x + 3(5x) + 4y - x =​
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Step-by-step explanation:

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7m

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Use the fact that the variance of a Poisson distribution is σ2=μ. The mean number of bankruptcies filed per hour by businesses i
lianna [129]

Answer:

Variance = 5

Standard deviation = 2.236

0.2650257

Step-by-step explanation:

For a Poisson distribution is σ² = μ.

Given that:

Mean , μ of bankruptcies files per hour = 5

μ = 5

For a Poisson distribution :

P(x = x) = (μ^x * e^-μ) / x!

The Variance and standard deviation :

Variance : σ² = μ = 5

Standard deviation = sqrt(variance) = sqrt(5) = 2.236

B.) Find the probability that at most three businesses will file bankruptcy in any given hour.

P( x ≤ 3) = P(0) + P(1) + P(2) + P(3)

P(x = 0) = (5^0 * e^-5) / 0! = 0.0067379

P(x = 1) = (5^1 * e^-5) / 1! = 0.0336897

P(x = 2) = (5^2 * e^-5) / 2! = 0.0842243

P(x = 3) = (5^3 * e^-5) / 3! = 0.1403738

0.0067379 + 0.0336897 + 0.0842243 + 0.1403738

= 0.2650257

6 0
3 years ago
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