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3 years ago

How do I do this question #2

Mathematics

2 answers:

lara [203]3 years ago

7 0

The answer is
75 to my think and my calculation
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sukhopar [10]3 years ago

5 0

The awnser is 75...........

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Write 5.712 × 10–^8 without exponents

blagie [28]

Answer:

517200000

Step-by-step explanation:

10 to the power of 8 is equal to 100000000

5.712 times 100000000 is equal to 571200000

Could I pls get brainliest I need one more to level up pls help me out

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8 0

2 years ago

What is eight divided by two sevenths

Vilka [71]

Answer:

Step-by-step explanation:

7 0

3 years ago

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Which expression is equivalent to (16 x Superscript 8 Baseline y Superscript negative 12 Baseline) Superscript one-half?.

loris [4]

To solve the problem we must know the Basic Rules of Exponentiation.

<h2>Basic Rules of Exponentiation</h2>

$x^ax^b = x^{(a+b)}$
$\dfrac{x^a}{x^b} = x^{(a-b)}$
$(a^a)^b =x^{(a\times b)}$
$(xy)^a = x^ay^a$

$x^{\frac{3}{4}} = \sqrt[4]{x^3}= (\sqrt[3]{x})^4$

The solution of the expression is $\dfrac{4x^4}{y^6}$ .

<h2>Explanation</h2>

Given to us

$(16x^8y^{12})^{\frac{1}{2}}$

Solution

We know that 16 can be reduced to $2^4$ ,

$=(2^4x^8y^{12})^{\frac{1}{2}}$

Using identity $(xy)^a = x^ay^a$ ,

$=(2^4)^{\frac{1}{2}}(x^8)^{\frac{1}{2}}(y^{12})^{\frac{1}{2}}$

Using identity $(a^a)^b =x^{(a\times b)}$ ,

$=(2^{4\times \frac{1}{2}})\ (x^{8\times\frac{1}{2}})\ (y^{12\times{\frac{1}{2}}})$

Solving further

$=2^2x^4y^{-6}$

Using identity $\dfrac{x^a}{x^b} = x^{(a-b)}$ ,

$=\dfrac{2^2x^4}{y^6}$

$=\dfrac{4x^4}{y^6}$

Hence, the solution of the expression is $\dfrac{4x^4}{y^6}$ .

Learn more about Exponentiation:

brainly.com/question/2193820

8 0

2 years ago

What are the next three terms of the following sequence?

kaheart [24]

we know that given terms were i geometric progression.

which means common ratio is same between two consecutive terms .

here we have 8,40,200,1000.

we know that common ratio =second term/first term =40/8=5.

so each and every terms is multiplied by 5 to get next term for this series the term after 1000 is 5000 =1000*5.

in part b we have another series which is having common ratio of -2.

so we need to multiply with -2 to find next term.

80*(-2)=-160.

for part c the common ratio is -2 .

so we need to multiply with -2 *previous term =-2*16 =-32.

5 0

3 years ago

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What the square root of 4

Aliun [14]

Answer:

Step-by-step explanation:

2x2=4

3 0

3 years ago

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