To get rid of
, you have to take the third root of both sides:
![\sqrt[3]{x^{3}} = \sqrt[3]{1}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7Bx%5E%7B3%7D%7D%20%3D%20%5Csqrt%5B3%5D%7B1%7D%20)
But that won't help you with understanding the problem. It is better to write
as a product of 2 polynomials:
From this we know, that
is the solution. Another solutions (complex roots) are the roots of quadratic equation.
Answer:
he circle has a radius of π inches, so use a radius of about 3.1 inches.
Step-by-step explanation:
The circumference of a circle can be described as the linear distance round the circle
The circumference of a circle = 2nr
n = 3.14
r = radius
the diameter is the straight line that passes through the centre of a circle and touches the two edges of the circle.
A radius is half of the diameter
diameter = 2r
If diameter = n2
diameter = 3.14 x 2 = 6.28
Radius = 1/2 x diameter = 6.28/2 = 3.1
Answer:
2
Step-by-step explanation:
f(x)=2x^2+9x-5
When we are find how many times it intersects the x axis, we are finding the zero's. Set the equation equal to zero
0=2x^2+9x-5
Factor the equation
0 = (2x+1) (x-5)
2*1
1*-5 = -5
2*-5 +1*1 = -9
This checks for the first last and middle terms so we factored correctly
Then using the zero product property
2x+1 = 0 and x-5 =0
2x = -1 x=5
x = -1/2 and x=5
This function crosses the x axis 2 times
Answer:
200
Step-by-step explanation:
200
Answer:
x = 5.5 (nearest tenth)
Step-by-step explanation:
let x be the length of 1 side
given area of square poster is 30 in²
and
Area = (length of 1 side )²
hence
30 = x²
x = √30
x = 5.4772
x = 5.5 (nearest tenth)
