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jasenka [17]
2 years ago
13

What meets a segment at its midpoint at a 90 degree angle?

Mathematics
1 answer:
marysya [2.9K]2 years ago
6 0

Answer:

The right angle's vertex.

Step-by-step explanation:

A right angle is 90 degrees. The vertex is at the middle of the angle, so that point is used to draw a segment in the middle of the right angle.

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Ruth buys 19 identical tickets for £280.25.<br> Estimate the cost of one ticket.
xxTIMURxx [149]

Answer:

The cost of one ticket is $14.75

Step-by-step explanation:

To find the cost of one ticket we need to divide 280.25 by 19

=$14.75

plz mark me as brainliest

3 0
3 years ago
Read 2 more answers
Vondra wants to buy a charm bracelet. Oak Grove Fine Jewelry charges $16 per charm, plus $53 for the bracelet. Sandoval Jewelers
AveGali [126]

Answer:

The bracelet will cost 85$ and it'll have 2 charms.

Step-by-step explanation:

In order to find the total cost of the bracelet and how many charms it'd be we need to build an equation for each store. So we have:

Oak Grove:

total cost = 16*charm + 53

Sandoval:

total cost = 27*charm + 31

We then find the number of charm that'll make them equal, since the price has to be the same on both shops:

16*charm + 53 = 27*charm + 31

27*charm - 16*charm = 53 - 31

11*charm = 22

charm = 2

The cost of the bracellet is:

total cost = 27*2 + 31 = 85 $

3 0
3 years ago
Read 2 more answers
Dr. Ashby is studying the heart rate of adult men. Preliminary data suggests that the standard deviation of heart rates for adul
jok3333 [9.3K]

Answer:

n=42 adult men

Step-by-step explanation:

-The minimum sample size to get a desired margin of error, E is calculated using the formula:

n\geq( \frac{z\sigma}{E})^2

-Given that \sigma=7.5, \ \ E=3\ , \ z_{0.005}=2.58, we can substitute to solve for n in the above formula:

n\geq (\frac{z\sigma}{E})^2\\\\\therefore n=(\frac{z_{\alpha/2}\sigma}{E})^2\\\\=(\frac{2.58\times7.5}{3})^2\\\\=41.6025\approx42

Hence, the desired minimum sample size, n is 42 adult men.

4 0
3 years ago
−2x=x^2−6
Iteru [2.4K]

Step-by-step explanation:

Example 1

Solve the equation x3 − 3x2 – 2x + 4 = 0

We put the numbers that are factors of 4 into the equation to see if any of them are correct.

f(1) = 13 − 3×12 – 2×1 + 4 = 0 1 is a solution

f(−1) = (−1)3 − 3×(−1)2 – 2×(−1) + 4 = 2

f(2) = 23 − 3×22 – 2×2 + 4 = −4

f(−2) = (−2)3 − 3×(−2)2 – 2×(−2) + 4 = −12

f(4) = 43 − 3×42 – 2×4 + 4 = 12

f(−4) = (−4)3 − 3×(−4)2 – 2×(−4) + 4 = −100

The only integer solution is x = 1. When we have found one solution we don’t really need to test any other numbers because we can now solve the equation by dividing by (x − 1) and trying to solve the quadratic we get from the division.

Now we can factorise our expression as follows:

x3 − 3x2 – 2x + 4 = (x − 1)(x2 − 2x − 4) = 0

It now remains for us to solve the quadratic equation.

x2 − 2x − 4 = 0

We use the formula for quadratics with a = 1, b = −2 and c = −4.

We have now found all three solutions of the equation x3 − 3x2 – 2x + 4 = 0. They are: eftirfarandi:

x = 1

x = 1 + Ö5

x = 1 − Ö5

Example 2

We can easily use the same method to solve a fourth degree equation or equations of a still higher degree. Solve the equation f(x) = x4 − x3 − 5x2 + 3x + 2 = 0.

First we find the integer factors of the constant term, 2. The integer factors of 2 are ±1 and ±2.

f(1) = 14 − 13 − 5×12 + 3×1 + 2 = 0 1 is a solution

f(−1) = (−1)4 − (−1)3 − 5×(−1)2 + 3×(−1) + 2 = −4

f(2) = 24 − 23 − 5×22 + 3×2 + 2 = −4

f(−2) = (−2)4 − (−2)3 − 5×(−2)2 + 3×(−2) + 2 = 0 we have found a second solution.

The two solutions we have found 1 and −2 mean that we can divide by x − 1 and x + 2 and there will be no remainder. We’ll do this in two steps.

First divide by x + 2

Now divide the resulting cubic factor by x − 1.

We have now factorised

f(x) = x4 − x3 − 5x2 + 3x + 2 into

f(x) = (x + 2)(x − 1)(x2 − 2x − 1) and it only remains to solve the quadratic equation

x2 − 2x − 1 = 0. We use the formula with a = 1, b = −2 and c = −1.

Now we have found a total of four solutions. They are:

x = 1

x = −2

x = 1 +

x = 1 −

Sometimes we can solve a third degree equation by bracketing the terms two by two and finding a factor that they have in common.

6 0
3 years ago
Read 2 more answers
Given: f(x) = 2x + 5, match the inputs with their outputs.
bekas [8.4K]
Yeah the answer is number 5
3 0
3 years ago
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