Select the correct answer from each drop-down menu. In the figure, ab, and both lines are intersected by transversal t. Complete
the statements to prove that m_1 = m 5.
allb (given)
m21 + m23 = 180° (Linear Pair Theorem)
m 5+ m26 = 180° (Linear Pair Theorem)
m 1 + m23 = 25+ 26(
m 3 = m_6
.)
m21 = m_5 (Subtraction Property of Equality)
allb (given)
m21 + m23 = 180° (Linear Pair Theorem)
m 5+ m26 = 180° (Linear Pair Theorem)
m 1 + m23 = 25+ 26(
m 3 = m_6
.)
m21 = m_5 (Subtraction Property of Equality)
1 answer:
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See the attached picture:
Answer:
maximum: y = 1
minimum: y = 0.
Step-by-step explanation:
Here we have the function:
y = f(x) = √(1 + x^2 - 2x)
we want to find the minimum and maximum in the segment [0, 1]
First, we evaluate in the endpoints, which are 0 and 1.
f(0) =√(1 + 0^2 - 2*0) = 1
f(1) = √(1 + 1^2 - 2*1) = 0
Now let's look at the critical points (the zeros of the first derivate)
To derivate our function, we can use the chain rule:
f(x) = h(g(x))
then
f'(x) = h'(g(x))*g(x)
Here we can define:
h(x) = √x
g(x) = 1 + x^2 - 2x
Then:
f(x) = h(g(x))
f'(x) = 1/2*( 1 + x^2 - 2x)*(2x - 2)
f'(x) = (1 + x^2 - 2x)*(x - 1)
f'(x) = x^3 - 3x^2 + x - 1
this function does not have any zero in the segment [0, 1] (you can look it in the image below)
Thus, the function does not have critical points in the segment.
Then the maximum and minimum are given by the endpoints.
The maximum is 1 (when x = 0)
the minimum is 0 (when x = 1)
