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Yuliya22 [10]
2 years ago
5

1/2 to the 2nd power in fraction form

Mathematics
1 answer:
Rzqust [24]2 years ago
5 0

Answer:  \frac{1}{4}

Work Shown:

\left(\frac{1}{2}\right)^2 = \left(\frac{1}{2}\right)*\left(\frac{1}{2}\right) = \frac{1*1}{2*2} = \frac{1}{4}

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a freight train leaves a station at noon traveling 30 mph. a passenger train leaves 1 your later traveling at 50 mph. at what ti
Stels [109]
I think it's 2.1 hours.
6 0
3 years ago
Rewrite 2x^2+13x+26/x+4 in the form q(x)+r(x)/b(x) . Then find q(x) and r(x).
natulia [17]
We are dividing the polynomial 2x^{2} +13x+26 by x+4

notice that 2x^{2} is x times 2x,

so if we multiply (x+4) by 2x, which gives us 2 x^{2} +8x, we can 'separate' one 2 x^{2} +8x from 2x^{2} +13x+26  to get the following simplification:

\frac{2x^{2} +13x+26}{x+4}= \frac{ 2x^{2}+8 x}{x+4} + \frac{5x+26}{x+4}=2x+ \frac{5x+26}{x+4}

similarly we notice that 5x is x times 5, so if we multiply (x+4) by 5, we get 5x+20 so we can rewrite 

\frac{5x+26}{x+4}= \frac{5x+20}{x+4}+  \frac{6}{x+4}=5+\frac{6}{x+4}

\frac{6}{x+4} can not be simplified any further since the degree of 6, is smaller than the degree of x+4

combining our work, we have:

\frac{2x^{2} +13x+26}{x+4}=2x+5+\frac{6}{x+4}

Answer:

q(x)= 2x+5
r(x)=6
b(x)=x+4


Remark: we can solve the problem by long division or the division algorithm as well.
6 0
3 years ago
Read 2 more answers
Fill in the blank to make each equality true. _ divided by (1/2x^3)=16x^6y^4.<br> PLS HELP!
viktelen [127]

Answer:

(8x^9 x y^4) : (1/2x^3)=16x^6y^4

Step-by-step explanation:

8 : 1/2 = 16

x^9 : x^3 = x^6

4 0
3 years ago
4.4 is what % of 25 ​
kirza4 [7]

4.4 = .044

0.044x25 = 1.1

ANSWER = 1.1

8 0
3 years ago
Read 2 more answers
What is the maximum integer value that satisfies the inequality 5x-11≤ 43?
Nitella [24]

Answer:

10

Step-by-step explanation:

We start by getting the value of x

We have this as follows:

5x ≤ 43 + 11

5x ≤ 54

x ≤ 54/5

x ≤ 10.8

As we can see, the maximum integer closest to this decimal is the value 10

7 0
3 years ago
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