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r-ruslan [8.4K]
4 years ago
9

Parallel lines and transversals

Mathematics
1 answer:
Ira Lisetskai [31]4 years ago
7 0
It is 54 degrees (fifty four)
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5x -2x +6x +40 -9 +1 -x +3x -8 +15x +7
creativ13 [48]
X=28582 that is the sender
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3 years ago
A pair of dice was rolled many times
nignag [31]

Answer: 7/24

Step-by-step explanation:

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In a school of 320 students, 85 students are in the band, 200 students are on sport teams, and 60 students participate in both a
Elenna [48]

Step-by-step explanation:

it is 55 cause if there were 200 tha. 155 were dead so only 55 lestf

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2 years ago
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I need help if anyone knows the answer please ASAP
mina [271]

Answer:

TE=11

Step-by-step explanation:

x^2+6x=x+14\\x^2+6x-x-14=0\\x^2+5x-14=0\\(x-2)(x+7)=0\\x=2\\x=-7\\

(you can't use -7 cuz that would make TE a negative distance and that's a nono)

x=2\\TE=6(2)-1\\=12-1\\=11

6 0
3 years ago
You want to obtain a sample to estimate a population proportion. At this point in time, you have no reasonable estimate for the
Vesna [10]

Answer:

A sample size of at least 1,353,733 is required.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of , we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of .

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

98% confidence level

So \alpha = 0.02, z is the value of Z that has a pvalue of 1 - \frac{0.02}{2} = 0.99, so Z = 2.327.  

You would like to be 98% confident that you esimate is within 0.1% of the true population proportion. How large of a sample size is required?

We need a sample size of at least n.

n is found when M = 0.001.

Since we don't have an estimate for the proportion, we use the worst case scenario, that is \pi = 0.5

So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.001 = 2.327\sqrt{\frac{0.5*0.5}{n}}

0.001\sqrt{n} = 2.327*0.5

\sqrt{n} = \frac{2.327*0.5}{0.001}

(\sqrt{n})^{2} = (\frac{2.327*0.5}{0.001})^{2}

n = 1353732.25

Rounding up

A sample size of at least 1,353,733 is required.

5 0
3 years ago
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