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1 year ago

10

Mrs. Figueroa made a spaghetti dinner for the cheerleaders after practice. She purchased 42 pounds of beef for $3.99 per pound.

How much money did she spend
on the beef for the spaghetti?
$7.25
$8.87
$9.98
$18.95

2 answers:

Zigmanuir [339]1 year ago

6 0

The answer is $167.58 you check it be multiplying 3.99x42

Marrrta [24]1 year ago

6 0

The answer is 167.58

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N is an integer. Prove that (2n+1)(n+3)+(2n+1)(n-2) is not a multiple of 2. thanks.

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Answer:

(2n + 1)(n + 3) + (2n + 1)(n - 2)

= (2n + 1)(n + 3 + n - 2)

= (2n + 1)2n + 1)

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Step-by-step explanation:

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Answer:

24 possible dishes

Step-by-step explanation:

Given

Total

$Meat = 4$

$Cheese = 3$

$Bread = 2$

Selection

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Required

Determine the number of possible combo

Rita wants to select 1 of 4 meat types,

So, the number of selections is: $^4C_1$

Rita wants to select 2 of 3 cheese types,

So, the number of selections is: $^3C_2$

Rita wants to select 1 of 2 cheese types,

So, the number of selections is: $^2C_1$

The total number of selections is:

$Total = ^4C_1 * ^3C_2 * ^2C_1$

Using

$^nC_r = \frac{n!}{(n-r)!r!}$

We have:

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$Total = \frac{4!}{3!1!} * \frac{3!}{1!2!} * \frac{2!}{(1!1!}$

$Total = \frac{4*3!}{3!*1} * \frac{3*2!}{1*2!} * \frac{2*1}{1*1}$

$Total = 4* 3 * 2$

$Total = 24$

<em>Hence, there are 24 possible dishes</em>

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