9 on the top as well so 9 x 2 18 3x2 6 3
The average rate of change, of the function, between the intervals, x = 2 to x = 6 is: 180.
<h3>What is the Average Rate of Change of a Function?</h3>
Average rate of change = 
.
Given the function, 
,
The average rate of change using the intervals of, x = 2 to x = 6 would be solved as shown below:
a = 2
b = 6
f(a) = 
= 34
f(b) = 
= 754
Average rate of change = 
Average rate of change = 180
Therefore, the average rate of change, of the function, between the intervals, x = 2 to x = 6 is: 180.
Learn more about average rate of change on:
brainly.com/question/8728504
It is not reasonable because if someone were to add 4 toppings, the price would be $20.41. However, if a person were to add 3 toppings using that equation, the price would $19.02.
Answer:
- c(n) = 320·0.96^n
- 28 years
Step-by-step explanation:
Each year, the class size is multiplied by 1 - 4% = 96% = 0.96. After n years, it has been multiplied by that number n times. Repeated multiplication is signified using an exponent.
Class size (c) can be modeled by ...
c(n) = 320·0.96^n
__
You want to find n such that c(n) = 100. Put in that value and solve.
100 = 320·0.96^n
100/320 = 0.96^n . . . . . . . divide by 320
log(100/320) = n·log(0.96) . . . . . . . take logs
log(100/320)/log(0.96) = n ≈ 28.4932
In about 28 years, the class will have 100 students.
=[5x-2]+[2x+1]
=5x-2+2x+1
=5x+2x-2+1
=7x-1
