Answer:
It would be the first one or second one
Step-by-step explanation:
the answer is up ahead
Answer:
a is the answer
Step-by-step explanation:
i got it right
The area bounded by the 2 parabolas is A(θ) = 1/2∫(r₂²- r₁²).dθ between limits θ = a,b...
<span>the limits are solution to 3cosθ = 1+cosθ the points of intersection of curves. </span>
<span>2cosθ = 1 => θ = ±π/3 </span>
<span>A(θ) = 1/2∫(r₂²- r₁²).dθ = 1/2∫(3cosθ)² - (1+cosθ)².dθ </span>
<span>= 1/2∫(3cosθ)².dθ - 1/2∫(1+cosθ)².dθ </span>
<span>= 9/8[2θ + sin(2θ)] - 1/8[6θ + 8sinθ +sin(2θ)] .. </span>
<span>.............where I have used ∫(cosθ)².dθ=1/4[2θ + sin(2θ)] </span>
<span>= 3θ/2 +sin(2θ) - sin(θ) </span>
<span>Area = A(π/3) - A(-π/3) </span>
<span>= 3π/6 + sin(2π/3) -sin(π/3) - (-3π/6) - sin(-2π/3) + sin(-π/3) </span>
<span>= π.</span>
Answer:
y = 2x - 3
Step-by-step explanation:
Parallel lines have the same slope
only the constant changes
y = 2x + b
To find "b"
Plug in point (3, 3)
3 = 2(3) + b
3 = 6 + b
Subtract 6 from both sides
-3 = b
The equation for the parallel line is
y = 2x - 3
Answer:
11
Step-by-step explanation:
Making the appropriate substitutions, we get
3/7 r + 5/8 s => 3/7 (14) + 5/8 (8).
Notice how this can reduced:
3(14) 5(8)
----------- + --------- = 6 + 5 = 11
7 8
