Answer:
you could make a number line with 11 lines and start at .04 and go to .05 so the 11 lines will be 0.04,0.041,0.042,0.043,0.044,0.045,0.046,0.047,0.048,0.049,0.05
and you could put a dot on 0.043
1.
![y=7x-1](https://tex.z-dn.net/?f=y%3D7x-1)
2.
<u> </u><u>Sub (1, -5) into equation to find '</u><em><u>b'</u></em><u />
3.
![x=-7](https://tex.z-dn.net/?f=x%3D-7)
4.
Answer:
Area = 634.21 square metre
Step-by-step explanation:
Area of shaded region = Area of the circle - Area of the sector
![Area \ of \ the \ circle = \pi r^2 = 225 \pi\\\\Area \ of \ the \ sector = \pi r^2 \frac{ \theta}{360} = \pi \times 225 \times \frac{37}{360}](https://tex.z-dn.net/?f=Area%20%5C%20of%20%5C%20the%20%5C%20circle%20%3D%20%5Cpi%20r%5E2%20%3D%20225%20%5Cpi%5C%5C%5C%5CArea%20%5C%20of%20%5C%20the%20%5C%20sector%20%3D%20%5Cpi%20r%5E2%20%5Cfrac%7B%20%5Ctheta%7D%7B360%7D%20%3D%20%5Cpi%20%5Ctimes%20225%20%5Ctimes%20%5Cfrac%7B37%7D%7B360%7D)
![Area \ of \ shaded \ region = 225 \pi - (225 \pi \times \frac{37}{360})](https://tex.z-dn.net/?f=Area%20%5C%20of%20%5C%20shaded%20%5C%20region%20%3D%20225%20%5Cpi%20-%20%28225%20%5Cpi%20%5Ctimes%20%20%5Cfrac%7B37%7D%7B360%7D%29)
![= 225 \pi (1 - \frac{37}{360})\\\\= 225 \pi \times 0.89722\\\\=634.21 m^2](https://tex.z-dn.net/?f=%3D%20225%20%5Cpi%20%281%20-%20%5Cfrac%7B37%7D%7B360%7D%29%5C%5C%5C%5C%3D%20225%20%5Cpi%20%5Ctimes%200.89722%5C%5C%5C%5C%3D634.21%20m%5E2)