Answer:
The value of the side PS is 26 approx.
Step-by-step explanation:
In this question we have two right triangles. Triangle PQR and Triangle PQS.
Where S is some point on the line segment QR.
Given:
PR = 20
SR = 11
QS = 5
We know that QR = QS + SR
QR = 11 + 5
QR = 16
Now triangle PQR has one unknown side PQ which in its base.
Finding PQ:
Using Pythagoras theorem for the right angled triangle PQR.
PR² = PQ² + QR²
PQ = √(PR² - QR²)
PQ = √(20²+16²)
PQ = √656
PQ = 4√41
Now for right angled triangle PQS, PS is unknown which is actually the hypotenuse of the right angled triangle.
Finding PS:
Using Pythagoras theorem, we have:
PS² = PQ² + QS²
PS² = 656 + 25
PS² = 681
PS = 26.09
PS = 26
Answer:
Widow's Share = Rs 500.05
Son's share = Rs 1400.14
Step-by-step explanation:
Property = 4000.40
Widow get share = 0.125
So, Share of Widow = 0.125 * 4000.40
Widow's Share = Rs 500.05
Remaining Property = 4000.40 - 500.05
Remaining Property = 3500.35
Son's share = 0.4 * 3500.35
Son's share = Rs 1400.14
5(1+9v) = 5+ 45v
20b+12= 4(5b+3)
And the last one is r=2
Hope this helps!
