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Virty [35]
3 years ago
13

Graph by making a table. y= -8x

Mathematics
1 answer:
VARVARA [1.3K]3 years ago
6 0
X      y
-5    40
-4    32
-3    24
-2    16
-1    8
0    0
1    -8
2    -16
3    -24
4    -32
5    -40

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Baba Clothing store is a having a 5% off sale on all of its clothing. Which expression represents the discounted price if p is t
Irina18 [472]

Answer:

The total of the prices of all of the baby shirts and sweaters that the store sold during the sale was $420.00. It's possible that 12 sweaters and 8 shirts are sold a bargen

Step-by-step explanation:

4 0
3 years ago
NEED HELP!!!!!!!!!!!!!
Nataliya [291]
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This means that </span><span> all the sides of the small figure are multiplied by the same number to obtain the lengths of the corresponding sides of the large figure.</span>
5 0
3 years ago
Q1W7 Learning Task 1 (Introduction)
Tatiana [17]

Answer:

Column A                                            Column B

1. x² + 6x + 8                                        x-3,x+2

2. x³ - 7x + 6                                       x+1, x+2, x+3

3. x³ - 2x² - 5x + 6                              x-1, x+2, x-3

Step-by-step explanation:

Column A                                            Column B

1. x² + 6x + 8                                        x-3,x+2

2. x³ - 7x + 6                                       x+1, x+2, x+3

3. x³ - 2x² - 5x + 6                              x-1, x+2, x-3

Using Factor theorem we put values of x = ±1,±2,±3 in each of the polynomials unless we get a zero.

1. x² + 6x + 8      

= 1+6(1) +8= 15

1. x² + 6x + 8

  4+ 12+8 = 24

1. x² + 6x + 8

 (-1)² + 6(-1)+ 8

= 1-6+8= 3

1. x² + 6x + 8

 (-2)² + 6(-2)+ 8

= 4-12+8= 0

1. x² + 6x + 8

(3)²+ 6(3) +8

= 9+18+8 ≠ 0

1. x² + 6x + 8

(-3)²+ 6(-3) +8

= 9-18+8 =-1

For this polynomial we have x+2= 0 or x=-2, x-3= 0 , x=3

2. x³ - 7x + 6

1-7+6= 0

2. x³ - 7x + 6

(-1)³-7(-1) +6

= 13-1≠0

2. x³ - 7x + 6

(2)³-7(2) +6

= 8-14+6= 0

2. x³ - 7x + 6

(-2)³-7(-2) +6

= -8 +14+6

2. x³ - 7x + 6

(-3)³-7(-3) +6

= -27+21+6 = 0

For this polynomial we have x+1= 0 , x+2 = 0  and x+3= 0, or x=-1,-2,-3

3. x³ - 2x² - 5x + 6

(1)³-2(1)²-5(1)+6

= 0

3. x³ - 2x² - 5x + 6

(-1)³-2(-1)²-5(-1)+6

= -1 -2 +5+6

=8

3. x³ - 2x² - 5x + 6

(2)³-2(2)²-5(2)+6

= 8-8-10+6

=-4

3. x³ - 2x² - 5x + 6

(-2)³-2(-2)²-5(-2)+6

= -8-8+10+6

=0

3. x³ - 2x² - 5x + 6

(3)³-2(3)²-5(3)+6

= 27-18-15+6

=0

3. x³ - 2x² - 5x + 6

(-3)³-2(-3)²-5(-3)+6

= -27-18+15+6

=-14

For this polynomial we have x-1= 0 ,x+2=0, x-3= 0or x=1,-2,3

7 0
3 years ago
Express f(x) = |x-2| +|x+2| in the non-modulus form. Hence, sketch the graph of f.
alexgriva [62]
Recall that

|x|=\begin{cases}x&\text{if }x\ge0\\-x&\text{if }x

There are three cases to consider:

(1) When x+2, we have |x+2|=-(x+2) and |x-2|=-(x-2), so

|x-2|+|x+2|=-(x-2)-(x+2)=-2x-4

(2) When x+2\ge0 and x-2, we get |x+2|=x+2 and |x-2|=-(x-2), so

|x-2|+|x+2|=-(x-2)+(x+2)=4

(3) When x-2\ge0, we have |x+2|=x+2 and |x-2|=x-2, so

|x-2|+|x+2|=(x-2)+(x+2)=2x

So

|x-2|+|x+2|=\begin{cases}-2x-4&\text{if }x
4 0
3 years ago
Solve this question ​
love history [14]

Answer:

\frac{4x - 11}{2}  \leqslant 3x - 3 < 4 \\  \\   =  > \frac{4x - 11}{2}  \leqslant 3x - 3 \: and \: 3x - 3 < 4 \\  \\  <  =  > 4x - 11 \leqslant 6x - 6 \:  \: and \:  \: 3x < 7 \\  \\  <  =  > 2x \geqslant  - 5 \:  \: and \:  \: x <  \frac{7}{3}  \\  \\  <  =  >  \frac{ - 5}{2}  \leqslant x <  \frac{7}{3}

=> the greatest integer is 2

the smallest integer is -2

3 0
3 years ago
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