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Oksana_A [137]
4 years ago
8

What do you add too 17/4 to make 5

Mathematics
1 answer:
MatroZZZ [7]4 years ago
7 0

Answer:

<u><em>3/4 </em></u><em>  </em>or<em>  </em><u><em>0.75</em></u>

Step-by-step explanation:

Let's add x to 17/4 to get to 5

Then, 17/4 + x = 5

x = 5 - 17/4

x = 20-17 / 4

x = 3/4

In short, Your Final Answer would be: 3/4 or 0.75

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First off, we factor out the expression:

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In the bracket, separate 8 out of the expression.

\displaystyle \large{y = 2[ ( {x}^{2} - 6x + 8)] }\\  \displaystyle \large{y = 2[ ( {x}^{2} - 6x) + 8]}

In x^2-6x, find the third term that can make up or convert it to a perfect square form. The third term is 9 because:

\displaystyle \large{ {(x - 3)}^{2}  =  {x}^{2}  - 6x + 9}

So we add +9 in x^2-6x.

\displaystyle \large{y = 2[ ( {x}^{2} - 6x + 9)  + 8]}

Convert the expression in the small bracket to perfect square.

\displaystyle \large{y = 2[  {(x - 3)}^{2}   + 8]}

Since we add +9 in the small bracket, we have to subtract 8 with 9 as well.

\displaystyle \large{y = 2[  {(x - 3)}^{2}   + 8 - 9]} \\  \displaystyle \large{y = 2[  {(x - 3)}^{2}   - 1]}

Then we distribute 2 in.

\displaystyle \large{y = 2[  {(x - 3)}^{2}   - 1]} \\

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