Question

If a = 1,b=2 and c=-3 find a^b-c b^c-a c^a-b

Answer 1

Answer:

The value of

$a {}^{b} - c \: b {}^{c} - a \: c {}^{a} - b \:$

is

$\frac { 19}{8}$

Step-by-step explanation:

Greetings !

$a {}^{b} - c \: b {}^{c} - a \: c {}^{a} - b$

where,

• a=1
• b=2
• c=-3

Thus, substitute these values to the given equation to find the values.

$a {}^{b} - c \: b {}^{c} - a \: c {}^{a} - b ... \: substitute \: \\ given \: values \\ (1) {}^{2} - ( - 3)(2) {}^{ - 3} - 1( - 3) {}^{1} - 2 \\ 1 + 3 \: ( \frac{1}{8} ) - 1( - 3) - 2 \\ 1 + \frac{3}{8} + 3 - 2 \\ \frac{11}{8} + 3 - 2 \\ \frac{35}{8} - 2 \\ \frac{19}{8} = 2 \frac{3}{8}$

Hope it helps