All categories

2 years ago

Helppppppppppppppppppp

Mathematics

1 answer:

bija089 [108]2 years ago

8 0

Answer:

To get the area of a parallelogram

Step-by-step explanation:

A=bh is the formula for an area so option D is definitely wrong.

The formula for the area of a triangle is $\frac{1}{2} *b*h$ .

The formula for the area of a circle is πr²

The formula for the area of a parallelogram is A=bh

A=bh is the formula for the area of a parallelogram.

You might be interested in

Mrs. Flores asked her students to write a number, its opposite, and its absolute value, in that order. Four of her students turn

oee [108]

Answer:

Sarah is correct

Step-by-step explanation:

Required

Which of the students is correct

Let a number be x,

Given what the teacher asked the students to do, the solution is:

$Number = x$

$Opposite = -x$

$Absolute = |x|$

Only Sarah got this correctly; others are incorrect.

The proof is as follows.

For Sarah

$Number = 1416$

$Opposite = -1416$

$Absolute =|1416| = 1416$

So, the numbers will be: 1416, -1416 and 1416

<em>Other students are incorrect</em>

4 0

2 years ago

whether the distribution of the mean of a large number of independent, identically distributed variables. true or false

san4es73 [151]

Answer:

The statement is false

Step-by-step explanation:

Given

See comment for complete statement

Required

Is the statement true or false

From central limit theorem, we understand that a distribution is approximately normal if the distribution takes a sample considered to be large enough from the population.

Also, the mean and the standard deviation are known.

However, the given statement implies that the distribution will be normal depending on an underlying distribution; this is false.

6 0

2 years ago

X is directly proportional with the square root of Y. If X=128 and Y=16 find: X when Y=36 B) Y when X=48 ( HELP ASAP!)

Tems11 [23]

x = sqrt{y}k

K is the constant of proportionality.

128 = sqrt{16}k

128 = 4k

128/4 = k

32 = k

x = sqrt{y}k

x = sqrt{36}•32

x = 6 • 32

x = 192

Find y when x = 48.

x = sqrt{y}k

48 = sqrt{y}32

48/32 = sqrt{y}

(48/32)^2 = [sqrt{y}]^2

2.25 = y

7 0

3 years ago

Solve each problem below. Show your steps. The Yellow Cab Company charges just $0.25 a mile, but it costs $5 to get in the cab.

Dmitry_Shevchenko [17]

14. $5+$.25x=y
15. $1.5x=y
16. Yellow cab, 5+.25(7)=6.75
17. Express cab, 1.5(3)=4.50

3 0

2 years ago

\cos ( 2x- \dfrac{ 3 \pi }{ 4 } ) = - \dfrac{ 1 }{ 2 }

satela [25.4K]

Answer:

$\displaystyle{x= \dfrac{17\pi}{24}+ \pi n, \dfrac{25\pi}{24}+\pi n \ \ \ (n \in \mathbb{I})}$

Step-by-step explanation:

Given the cosine equation:

$\displaystyle{\cos \left(2x - \dfrac{3\pi}{4}\right) = -\dfrac{1}{2}}$

Let:

$\displaystyle{\theta = 2x - \dfrac{3\pi}{4}}$

Then we will have:

$\displaystyle{\cos \theta = -\dfrac{1}{2}}$

We know that cosθ is negative in second quadrant and third quadrant.

In second quadrant:

$\displaystyle{\pi - \dfrac{\pi}{3}}\\\\\displaystyle{=\dfrac{3\pi}{3} - \dfrac{\pi}{3}}\\\\\displaystyle{=\dfrac{2\pi}{3}}$

In third quadrant:

$\displaystyle{\pi + \dfrac{\pi}{3}}\\\\\displaystyle{=\dfrac{3\pi}{3} + \dfrac{\pi}{3}}\\\\\displaystyle{=\dfrac{4\pi}{3}}$

Therefore, we will have two solutions where:

$\displaystyle{\theta_1 = \dfrac{2\pi}{3}}\\\displaystyle{\theta_2 = \dfrac{4\pi}{3}}$

Convert from theta back to the original expression:

$\displaystyle{2x_1-\dfrac{3\pi}{4}= \dfrac{2\pi}{3}}\\\\\displaystyle{2x_2-\dfrac{3\pi}{4}= \dfrac{4\pi}{3}}$

Convert two equations into one:

$\displaystyle{2x-\dfrac{3\pi}{4}= \dfrac{2\pi}{3}, \dfrac{4\pi}{3}}$

Since you do not specify the interval, add $\displaystyle{2\pi n}$ where $\displaystyle{n \in \mathbb{I}}$ .

$\displaystyle{2x-\dfrac{3\pi}{4}= \dfrac{2\pi}{3}+2\pi n, \dfrac{4\pi}{3}+2\pi n}$

Solve the equation for x:

$\displaystyle{2x= \dfrac{2\pi}{3}+\dfrac{3\pi}{4}+2\pi n, \dfrac{4\pi}{3}+\dfrac{3\pi}{4}+2\pi n}\\\\\displaystyle{2x= \dfrac{8\pi}{12}+\dfrac{9\pi}{12}+2\pi n, \dfrac{16\pi}{12}+\dfrac{9\pi}{12}+2\pi n}\\\\\displaystyle{2x= \dfrac{17\pi}{12}+2\pi n, \dfrac{25\pi}{12}+2\pi n}\\\\\displaystyle{x= \dfrac{17\pi}{24}+ \pi n, \dfrac{25\pi}{24}+\pi n}$

Therefore, the solution is:

$\displaystyle{x= \dfrac{17\pi}{24}+ \pi n, \dfrac{25\pi}{24}+\pi n \ \ \ (n \in \mathbb{I})}$

3 0

1 year ago

Helppppppppppppppppppp​

Helppppppppppppppppppp