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butalik [34]
1 year ago
11

A dog is 9 times as heavy as a cat, a hamster is 20 times as light as a cat, and a mouse is 6 times as heavy as the hamster. How

many times is the dog as heavy as a mouse?​
Mathematics
1 answer:
Angelina_Jolie [31]1 year ago
4 0

Answer:

30

Step-by-step explanation:

Let the cat have a weight of x.

Then, the dog weighs 9x.

The hamster weighs x/20.

The mouse weighs 3x/10.

So, the dog is 9/(3/10) = 30 times as heavy.

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9 more than a number is equal to 10
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Answer:

1

Step-by-step explanation:

9 + 1 is equal to 10. Therefore, the answer is 1.

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2 years ago
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Randy has 128 ounces of dog food.he feeds his dog 8ounces of food each day.how many days will the dog food last?
pentagon [3]
The dog food food will last for 16 days
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3 years ago
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The following graph represents the distance a commercial airplane travels over time, at cruising speed and an altitude of 35,000
ANEK [815]

Answer:

see the explanation

Step-by-step explanation:

<u><em>The picture of the question in the attached figure</em></u>

we know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form k=\frac{y}{x} or y=kx

In a proportional relationship the constant of proportionality k is equal to the slope m of the line and the line passes through the origin

Let

x ----> the time in hours

y ----> the distance in miles

<em>Find the value of k</em>

For the point (4,2268)

k=\frac{2,268}{4}=567\ mph

The slope represent the speed of the airplane

so

The linear equation is

y=567x

Part 1 :

The point (0,0) represents the starting point of the aircraft, when the time and distance are equal to zero. The cruising starts when time t = 0.

Part 2 :

The  point  (4, 2268) represents the plane after 4 hours of cruise , and shows it has traveled a distance of 2268 miles after 4 hours

3 0
3 years ago
Number 2 I need help on how to solve it
Hunter-Best [27]

Let's simplify the following expression:

\text{ }\frac{\text{ \lparen2x}^4\text{ - y}^6\text{z}^{-4})^2}{\text{ 2x}^2\text{z}^3}\text{ }\cdot\text{ }\frac{\text{ 6x}^5\text{y}^{-4}\text{z}^{-5}}{\text{ \lparen2x}^6\text{y}^3\text{z}^{-3})^2}

We get,

\text{ }\frac{(\text{2x}^4\text{ - y}^6\text{z}^{-4})^2}{\text{ 2x}^2\text{z}^3}\text{ }\cdot\text{  }\frac{6x^5y^{-4}z^{-5}}{(2x^6y^3z^{-3})^2}\text{ }\frac{(2x^4-y^6z^{-4})^2(6x^5y^{-4}z^{-5})}{(2x^2z^3)(2x^6y^3z^{-3})^2}\text{ }\frac{(4x^8\text{ - 4x}^4y^6z^{-4}\text{ + y}^{12}z^{-8})(6x^5y^{-4}z^{-5})}{(2x^2z^3)(4x^{12}y^6z^{-6})}\text{ }\frac{24x^{13}y^{-4}z^{-5}\text{ - 24x}^9y^2z^{-9}\text{ + 6x}^5y^8z^{-13}}{8x^{14}y^6z^{-3}}

4 0
1 year ago
Yesterday Consuela bought some fudge and caramels for $6. She bought 2 pieces of fudge at 50 cents a piece and some caramels at
lana [24]
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5 0
3 years ago
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