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2 years ago

Lesson 5 Practice Problems

Mathematics

1 answer:

Vlad1618 [11]2 years ago

7 0

Answer:

Step-by-step explanation:

The required value of equation at x = 5 is 24.

Given ;

Equation is = 4(x-2)(x-3) + 7(x-2)(x-5) - 6(x-3)

We have to calculate the value of expression when x = 5

To solve the equation substitute x = 5 in the given equation

= 4(x-2)(x-3) + 7(x-2)(x-5) - 6(x-3)(x-5)

= 4(5-2)(5-3) + 7(5-2)(5-5) - 6(5-3)(5-5)

Simplify the equation

= 4(3)(2) + 7(3)(0) - 6(2)(0)

= 4.(6) + 7(0) - 6(0)

= 24 + 0 - 0

= 24

The required value of the equation at x = 5 is 24.

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Answer:

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Step-by-step explanation:

The given function is

$f(x,y,z)=4x\sin (y-z)$

We need to find first partial derivatives of the function.

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Differentiate partially w.r.t. y and x, z are constants.

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$f_y(x,y,z)=4x\cos (y-z)$

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Therefore, the first partial derivatives of the function are $f_x(x,y,z)=4\sin (y-z), f_x(x,y,z)=4x\cos (y-z)\text{ and }f_z(x,y,z)=-4x\cos (y-z)$ .

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Answer:

Step-by-step explanation:

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