What value of z* should be used to construct a 97 confidence interval of a population mean?
1 answer:
The value of z* should be used to construct a 97 confidence interval of a population mean is 2.17.
<h3>What is confidence interval?</h3>A degree of uncertainty and certainty in a sample process is measured by confidence intervals. They can choose from a variety of probability limitations, the most frequent becoming a 95% or 99% confidence level.
Some characteristics of confidence interval are-
- Statistical tools, such as the t-test, are used to compute confidence intervals.
- Confidence intervals are used by statisticians to quantify uncertainty in such a sample variable.
- A researcher, for example, may randomly select multiple samples drawn from the same population and compute a confidence interval for every sample to determine how well it might represent the real value of a population variable.
- The generated datasets are all unique; some intervals contain the genuine population parameter while others do not.
Now, according to the question;
The confidence level is given 97%.
Thus, the crucial value of z for a 97% confidence interval is 2.17, as determined by a z score table, which is as follows:
Therefore the obtained probability for the z-score of 2.17 is 0.97.
To know more about the confidence interval, here
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The series is -10-2+6+14+...+110
We see that the common ratio is 8, so it is of the form T0+8n
We also see that T0=-10 (i.e. when the pattern starts.
So we have
Tn=-10+8n
and the summation would be
∑ (-10+8n)
Next to determine the limits.
We know that the first term is -10, which fits T0=-10+8(0).
The last term is 110, which gives the equation Tn=110=-10+8(n)
Solving for n gives
n=(110+10)/8=15
Therefore the limits of summation are 0, 15
hence the summation formula is
I will leave the other problem you posted for your own exercise.
We see that the common ratio is 8, so it is of the form T0+8n
We also see that T0=-10 (i.e. when the pattern starts.
So we have
Tn=-10+8n
and the summation would be
∑ (-10+8n)
Next to determine the limits.
We know that the first term is -10, which fits T0=-10+8(0).
The last term is 110, which gives the equation Tn=110=-10+8(n)
Solving for n gives
n=(110+10)/8=15
Therefore the limits of summation are 0, 15
hence the summation formula is
I will leave the other problem you posted for your own exercise.