Answer:
x= -10/3
y= -8/9
Step-by-step explanation:
2x+1=3(y−1);6(2y−1)=5x
Rewrite equations:
2x+1=3y−3;12y−6=5x
Step: Solve2x+1=3y−3for x:
2x+1=3y−3
2x+1+−1=3y−3+−1(Add -1 to both sides)
2x=3y−4
2x2=3y−42(Divide both sides by 2)
x=32y−2
Step: Substitute32y−2forxin12y−6=5x:
12y−6=5x
12y−6=5(32y−2)
12y−6=152y−10(Simplify both sides of the equation)
12y−6+−152y=152y−10+−152y(Add (-15)/2y to both sides)
92y−6=−10
92y−6+6=−10+6(Add 6 to both sides)
92y=−4
92y92=−492(Divide both sides by 9/2)
y=−89
Step: Substitute−89foryinx=32y−2:
x=32y−2
x=32(−89)−2
x=−103(Simplify both sides of the equation)
It is all the way simplfyed all the way, I hope that that answers your question☻
(12,-24)
x intercept is 12 & y intercept is -24
Answer:
12
Step-by-step explanation:
The equation computed shows that the numbers will be 9, 11 and 13.
<h3>How to illustrate the information?</h3>
Let the numbers be:
First number = x
Second number = x + 2,
Third number = x + 4.
Total of the numbers = 33
The equation will be:
= first + second + third number
x + x + 2 + x + 4 = 33
3x + 6 = 33
Collect like terms
3x = 33 - 6
3x = 27.
Divide both side by 3
3x/3 = 27/3
x = 9
First number = x = 9
Second number = x + 2 = 9 + 2 = 11
Third number = x + 4. = 9 + 4 = 13
The numbers will be 9, 11, and 13.
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Illustrate the equation to find three consecutive odd integers whose sum is 33.