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1 year ago

6

A restaurant needs pound 7/8 of cinnamon. The price of cinnamon is $20 per pound. How much does the restaurant spend on cinnamon

?
Write the answer as a decimal to 2 places .)

1 answer:

Lorico [155]1 year ago

4 0

Answer:

$17.50

Step-by-step explanation:

Multiply 7/8 by 20/1, to find 7/8 of $20.00.

7/8 × 20/1 = 140/8

140 ÷ 8 = 17.5

Once you convert to money, this is $17.50.

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The smallest possible length is 0.83m

Step-by-step explanation:

Given

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Required

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This gives:

$565L= Length^3$

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$\frac{565m^3}{1000} = Length^3$

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2 years ago

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3 years ago

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You are at a stall at a fair where you have to throw a ball at a target. There are two versions of the game. In the first

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Answer:

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And the probability of loss with the first wersion is 0.729

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And the probability of loss with the first wersion is 0.774

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Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Alternative 1

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=3, p=0.1)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

We can find the probability of loss like this P(X=0) and if we find this probability we got this:

$P(X=0)=(3C0)(0.1)^0 (1-0.1)^{3-0}=0.729$

And the probability of loss with the first wersion is 0.729

Alternative 2

Let Y the random variable of interest, on this case we now that:

$Y \sim Binom(n=5, p=0.05)$

The probability mass function for the Binomial distribution is given as:

$P(Y)=(nCy)(p)^y (1-p)^{n-y}$

Where (nCx) means combinatory and it's given by this formula:

$nCy=\frac{n!}{(n-y)! y!}$

We can find the probability of loss like this P(Y=0) and if we find this probability we got this:

$P(Y=0)=(5C0)(0.05)^0 (1-0.05)^{5-0}=0.774$

And the probability of loss with the first wersion is 0.774

As we can see the best alternative is the first version since the probability of loss is lower than the probability of loss on version 2.

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