Answer:
Step-by-step explanation:
Hello,
a and b are the zeros, we can say that
So we can say that
Now, we are looking for a polynomial where zeros are 2a+3b and 3a+2b
for instance we can write
and we can notice that
so
![(x-2a-3b)(x-3a-2b)=x^2-5(a+b)x+6[(a+b)2-2ab]+13ab\\= x^2-5(a+b)x+6(a+b)^2+ab](https://tex.z-dn.net/?f=%28x-2a-3b%29%28x-3a-2b%29%3Dx%5E2-5%28a%2Bb%29x%2B6%5B%28a%2Bb%292-2ab%5D%2B13ab%5C%5C%3D%20x%5E2-5%28a%2Bb%29x%2B6%28a%2Bb%29%5E2%2Bab)
it comes
multiply by 3
I got 9.8 but if you want to round it you get 10 because you add 106 and 9 to get 115 and then add 3 and get 118 and then divide 12b and 118 and get 9.8
The answer to this question is A. 3
With a ratio, you should think of it in terms of a pie of sorts. In this example, the pie has 13 pieces, 9 of which consist of the perimeter of the large parallelogram and 4 of which consist of the perimeter of the smaller parallelogram. If we know that those 4 pieces of pie and equal to 20 units, then we would divide 20 by 4 to find the value of a single piece. 20/4=5 so a single piece of pie has a value of 5 units. We would then multiply 9 by 5 to find the value equivalent of the 9 pieces of pie. 9(5)=45. Therefore, the perimeter of the larger parallelogram is 45.
