All categories

2 years ago

Any tips for doing complicated order of operation problems. Algebra 2

1 answer:

3 0

This video can help you

https://www.khanacademy.org/math/cc-sixth-grade-math/x0267d782:cc-6th-exponents-and-order-of-operations/cc-6th-order-of-operations/v/more-complicated-order-of-operations-example

You might be interested in

Solve the system of equations.<br> 7x−3y=20<br> y=5x−4<br> x= <br> y=

Rama09 [41]

Answer:

{x,y} = {-1,-9}

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

What is the discriminant of 9x^2+=10x

prisoha [69]

9x^2-10x=0
D= b^2-4ac
b=-10
a=9
c=0
D=(-10)^2-4*9*0=10^2-0=100

4 0

3 years ago

Find the tangent line approximation for 10+x−−−−−√ near x=0. Do not approximate any of the values in your formula when entering

Svetllana [295]

Answer:

$L(x)=\sqrt{10}+\frac{\sqrt{10}}{20}x$

Step-by-step explanation:

We are asked to find the tangent line approximation for $f(x)=\sqrt{10+x}$ near $x=0$ .

We will use linear approximation formula for a tangent line $L(x)$ of a function $f(x)$ at $x=a$ to solve our given problem.

$L(x)=f(a)+f'(a)(x-a)$

Let us find value of function at $x=0$ as:

$f(0)=\sqrt{10+x}=\sqrt{10+0}=\sqrt{10}$

Now, we will find derivative of given function as:

$f(x)=\sqrt{10+x}=(10+x)^{\frac{1}{2}}$

$f'(x)=\frac{d}{dx}((10+x)^{\frac{1}{2}})\cdot \frac{d}{dx}(10+x)$

$f'(x)=\frac{1}{2}(10+x)^{-\frac{1}{2}}\cdot 1$

$f'(x)=\frac{1}{2\sqrt{10+x}}$

Let us find derivative at $x=0$

$f'(0)=\frac{1}{2\sqrt{10+0}}=\frac{1}{2\sqrt{10}}$

Upon substituting our given values in linear approximation formula, we will get:

$L(x)=\sqrt{10}+\frac{1}{2\sqrt{10}}(x-0)$

$L(x)=\sqrt{10}+\frac{1}{2\sqrt{10}}x-0$

$L(x)=\sqrt{10}+\frac{\sqrt{10}}{20}x$

Therefore, our required tangent line for approximation would be $L(x)=\sqrt{10}+\frac{\sqrt{10}}{20}x$ .

8 0

3 years ago

Help asap for brainlist help asap

Mariana [72]

Answer:

2x^3+11x^2-43x-24

Step-by-step explanation:

desmos graphing calculator- both factors matched

8 0

2 years ago

Suppose a triangle has two sides of length 42 and 35, and that the angle between these two sides is 120 degrees. What is the len

FrozenT [24]

Answer:

Option D

Step-by-step explanation:

The questions which involve calculating the angles and the sides of a triangle either require the sine rule or the cosine rule. In this question, the two sides that are given are adjacent to each other and the given angle is the included angle. This means that the angle is formed by the intersection of the two lines. Therefore, cosine rule will be used to calculate the length of b. The cosine rule is:

b^2 = a^2 + c^2 - 2*a*c*cos(B).

The question specifies that a=42, B=120°, and c=35. Plugging in the values:

b^2 = 42^2 + 35^2 - 2(42)(35)*cos(120°).

Simplifying gives:

b^2 = 4459.

Taking square root on the both sides gives b = 66.78 (rounded to the two decimal places).

This means that the length of the third side is 66.78 units!!!

7 0

3 years ago