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madam [21]
3 years ago
10

Circle L is shown. Line segments K L and M L are radii. The length of K L is 12. Angle M L K is 60 degrees. Sector M L K with a

60 degree angle is shaded. What is the area of the sector that is not shaded?
Mathematics
2 answers:
nadya68 [22]3 years ago
7 0

Answer:

120Pi units squared

Step-by-step explanation:

Do the math

kozerog [31]3 years ago
3 0

Answer:

Area of Un-shaded Sector is 376.99

Step-by-step explanation:

From the information given, we can say:

Radius of Circle = 12 (Since KL is radius and KL = 12)

The sector of shaded area covers 60 degrees

Total circle is 360, so unshaded sector is:

360 - 60 = 300 degrees

So, to find Non-Shaded Sector Area, we use sector area formula:

A=\frac{\theta}{360}*\pi r^2

Where

\theta  is the angle of the sector (in our case, it is 300)

So we substitute and find the answer:

A=\frac{300}{360}*\pi (12)^2\\A=\frac{5}{6}*\pi*144\\A=120\pi\\A=376.99

The area is 376.99

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WITCHER [35]

Answer:

Part 1) A=36(\pi-2)\ cm^2

Part 2) P=6(\pi+2\sqrt{2})\ cm

Step-by-step explanation:

<u><em>The picture of the question in the attached figure</em></u>

Part 1) Find the area

we know that

The area of the shape is equal to the area of a quarter of circle minus the area of an isosceles right triangle

so

A=\frac{1}{4}\pi r^{2}-\frac{1}{2}(b)(h)

we have that the base and the height of triangle is equal to the radius of the circle

r=12\ cm\\b=12\ cm\\h=12\ cm

substitute

A=\frac{1}{4}\pi (12)^{2}-\frac{1}{2}(12)(12)\\A=(36\pi-72)\ cm^2

simplify

Factor 36

A=36(\pi-2)\ cm^2

Part 2) Find the perimeter

The perimeter of the figure is equal to the circumference of a quarter of circle plus the hypotenuse of the right triangle

The circumference of a quarter of circle is equal to

C=\frac{1}{4}(2\pi r)=\frac{1}{2}\pi r

substitute the given values

C=\frac{1}{2}\pi (12)\\C=6\pi\ cm

Applying the Pythagorean Theorem

The hypotenuse of right triangle is equal to

AC=\sqrt{12^2+12^2}\\AC=\sqrt{288}\ cm

simplify

AC=12\sqrt{2}\ cm

Find the perimeter

P=(6\pi+12\sqrt{2})\ cm

simplify

Factor 6

P=6(\pi+2\sqrt{2})\ cm

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