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gladu [14]
2 years ago
13

A tennis supply store pays a wholersale $90 for a tennis racquet and sells it for $114. What is the markup rate?

Mathematics
1 answer:
damaskus [11]2 years ago
8 0

First, what you want to do is subtract the price you sell it for by how much you got it for.

In this case, your equation would look like this: 114 - 90 = 24

You added $24 to the price that you bought. The amount added to the price would be $24

Then you would divide the amount added to the price by the amount it costed you to buy. It would end up as a decimal:

24 ÷ 90 = 0.266 (infinite 6's)

Then with the decimal you got, you would multiply it by 100 to get the markup rate percentage.

0.266 × 100 = 26.66

The markup rate would be 26.66% (26.7 if you round).


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Evaluate a-b if a=10 and b=-7​
Tomtit [17]
10- -7 = 10 + 7 = 17!
7 0
2 years ago
Brian invests ?1900 into a savings account. The bank gives 3.5% compound interest for the first 2 years and 4.9% thereafter. How
Scorpion4ik [409]

let's check how much is it after 2 years firstly.


\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &1900\\ r=rate\to 3.5\%\to \frac{3.5}{100}\dotfill &0.035\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{yearly, thus once} \end{array}\dotfill &1\\ t=years\dotfill &2 \end{cases} \\\\\\ A=1900\left(1+\frac{0.035}{1}\right)^{1\cdot 2}\implies A=1900(1.035)^2\implies A=2035.3275


Brian invested the money for 6 years, so now let's check how much is that for the remaining 4 years.


\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &2035.3275\\ r=rate\to 4.9\%\to \frac{4.9}{100}\dotfill &0.049\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{yearly, thus once} \end{array}\dotfill &1\\ t=years\dotfill &4 \end{cases}


\bf A=2035.3275\left(1+\frac{0.049}{1}\right)^{1\cdot 4}\implies A=2035.3275(1.049)^4 \\\\\\ A\approx 2464.54\implies \boxed{\stackrel{\textit{rounded up }}{A=2465}}

4 0
3 years ago
the parallel sides of a trapezium are such that the longer side is 4cm more than the shorter side of the distance between them i
saw5 [17]

Answer:

32cm and 28cm

Step-by-step explanation:

Area of a trapezium=0.5 ( sum of parallel sides ) × height

600=0.5( 4+a+a)×20

where a is the length of the shorter side

600÷0.5=(4+2a)×20

1200=(4+2a)×20

1200÷20=4+2a

60=4+2a

60-4=2a

56=2a

56÷2=a

28=a.

since the longer side is 4 cm more than th shorter side , 28 +4=32

4 0
3 years ago
What is the difference between adding whole numbers and adding decimals?
noname [10]

Answer:

The only difference is that we line up the numbers according to the decimal point. For addition, it doesn't matter which number goes on the bottom.

4 0
2 years ago
Find the rule and the graph of the function whose graph can be obtained by performing the translation 3 units left and 2 units d
Leya [2.2K]

Answer: Option a.

Step-by-step explanation:

 1. You have the following parent function given in the problem above:

f(x)=x³ (This is the simplest form. We need to translate it 3 units left and 2 units down)

2. If you take the parent function and make y=f(x+3), then you have:

y=f(x+3)=(x+3)^{3} (The function is shifted 3 units left on the x-axis).

3. Then you if you make y=f(x+3)-2, as following, you obtain:

y=f(x+3)-2=(x+3)^{3}-2  (The function is shifted 2 units down on the y-axis).

4. Therefore, that is how you obtain the final function.

The answer is the graph shown in the option a.

6 0
3 years ago
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