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Allisa [31]
1 year ago
10

A gardener has 520 feet of fencing to fence in a rectangular garden. One side of the garden is bordered by a river and so it doe

s not need any fencing.
garden bordered by a river

What dimensions would guarantee that the garden has the greatest possible area?

shorter side: _____ft (feet)

longer side: ____ft (feet)

greatest possible area: ___ft2 (square-feet)
Mathematics
1 answer:
Bond [772]1 year ago
7 0

The shortest side is 130 feet, the longest side is 260 feet and the greatest possible area is 33800 square feet

<h3>What dimensions would guarantee that the garden has the greatest possible area?</h3>

The given parameter is

Perimeter, P = 520 feet

Represent the shorter side with x and the longer side with y

One side of the garden is bordered by a river:

So the perimeter is:

P = 2x + y

Substitute P = 520

2x + y = 520

Make y the subject

y = 520 - 2x

The area is

A = xy

Substitute y = 520 - 2x in A = xy

A = x(520 - 2x)

Expand

A = 520x - 2x^2

Differentiate

A' = 520 - 4x

Set to 0

520 - 4x = 0

Rewrite as:

4x= 520

Divide by 4

x= 130

Substitute x= 130 in y = 520 - 2x

y = 520 - 2 *130

Evaluate

y = 260

The area is then calculated as:

A = xy

This gives

A = 130 * 260

Evaluate

A = 33800

Hence, the shortest side is 130 feet, the longest side is 260 feet and the greatest possible area is 33800 square feet

Read more about area at:

brainly.com/question/24487155

#SPJ1

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katovenus [111]

Number of dimes collected is 339 and number of nickels collected is 113

<em><u>Solution:</u></em>

Given that There is a total of $39.55

There are 3 times as many dimes as nickels

To find: Number of dimes and nickels collected

Let "d" be the number of dimes collected

Let "n" be the number of nickels collected

We know that,

1 dime = $ 0.10

1 nickel = $ 0.05

From given information,

There are 3 times as many dimes as nickels

So, we get

Number of dimes = 3(number of nickels)

d = 3n

Given that there is total of $ 39.55

number of dimes collected x value of 1 dime + number of nickels collected x value of 1 nickel =  $ 39.55

3n \times 0.10 + n \times 0.05 = 39.55\\\\0.3n + 0.05n = 39.55\\\\0.35n = 39.55\\\\n = \frac{39.55}{0.35}\\\\n = 113

Substitute n = 113 in d = 3n

d = 3(113) = 339

<em><u>Summarizing the results:</u></em>

number of dimes collected = 339

number of nickels collected = 113

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