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ser-zykov [4K]
3 years ago
13

Solve each equation. d(d+3)-d(d-4)=9d-16

Mathematics
1 answer:
likoan [24]3 years ago
3 0

Answer:

2d+3d-2d+4d= 9d-16

2d is cancelled

3d+4d=9d-16

7d=9d-16

16=9d-7d

16=2

16/2

d=8

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Let’s look at another one of Homer’s rocket launches. It was launched from ground level with an initial velocity of 208 feet per
kozerog [31]

Answer:

Smax = 676 ft

the maximum altitude (height) the rocket will attain during its flight is 676 ft

Step-by-step explanation:

Given;

The height function S(t) of the rocket as;

S(t) = -16t2 + 208t

The maximum altitude Smax, will occur at dS/dt = 0

differentiating S(t);

dS/dt = -32t + 208 = 0

-32t +208 = 0

32t = 208

t = 208/32

t = 6.5 seconds.

The maximum altitude Smax is;

Substituting t = 6.5 s

Smax = -16(6.5)^2 + 208(6.5)

Smax = 676 ft

the maximum altitude (height) the rocket will attain during its flight is 676 ft

8 0
3 years ago
What is the slope of (-3,-2) and (-1,-5)
klio [65]

Answer:

-3/2

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
1/2 n + 3 = 6 please the answer thank u
spin [16.1K]

Answer:

Step-by-step explanation:

1/2 n + 3 = 6

-3 -3

1/2 = 3

Answer is 1.5=n

6 0
3 years ago
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Write down in terms of n,
mojhsa [17]
A) is counting down by 3
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4 0
3 years ago
The augmented matrix of a system of equations has been transformed to an equivalent matrix in​ row-echelon form. Using​ x, y
jenyasd209 [6]

Answer: The system of equations is:

x + 2y + 2 = 4

y - 3z = 9

z = - 2

The solution is: x = -22; y = 15; z = -2;

Step-by-step explanation: ONe way of solving a system of equations is using the Gauss-Jordan Elimination.

The method consists in transforming the system into an augmented matrix, which is writing the system in form of a matrix and then into a <u>Row</u> <u>Echelon</u> <u>Form,</u> which satisfies the following conditions:

  • There is a row of all zeros at the bottom of the matrix;
  • The first non-zero element of any row is 1, which called leading role;
  • The leading row of the first row is to the right of the leading role of the previous row;

For this question, the matrix is a Row Echelon Form and is written as:

\left[\begin{array}{ccc}1&2&2\\0&1&3\\0&0&1\end{array}\right]\left[\begin{array}{ccc}4\\9\\-2\end{array}\right]

or in system form:

x + 2y + 2z = 4

       y + 3z = 9

               z = -2

Now, to determine the variables:

z = -2

y + 3(-2) = 9

y = 15

x + 30 - 4 = 4

x = - 22

The solution is (-22,15,-2).

4 0
3 years ago
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