(12y)+12 y=15 do I multiply 12 and 15 then add 12

2 answers:

8 0

12y + 12.....when y = 15
12(15) + 12.....multiplication comes before addition in the order of operations...so multiply first.
so yes....u r correct...multiply 12 and 15, then add 12

My name is Ann [436]3 years ago

7 0

Yes you were right cause you have to do what is inside of the parenthesis first so that would be 180 then u would add 12.

your final answer would be 192

hope this was enough help

You might be interested in

Please help me with number #3 and check if the others are correct please I really need help

Sveta_85 [38]

All I can say is 1 and 2 are correct.

6 0

3 years ago

Evaluate c (y + 7 sin(x)) dx + (z2 + 9 cos(y)) dy + x3 dz where c is the curve r(t) = sin(t), cos(t), sin(2t) , 0 ≤ t ≤ 2π. (hin

saw5 [17]

Treat $\mathcal C$ as the boundary of the region $\mathcal S$ , where $\mathcal S$ is the part of the surface $z=2xy$ bounded by $\mathcal C$ . We write

$\displaystyle\int_{\mathcal C}(y+7\sin x)\,\mathrm dx+(z^2+9\cos y)\,\mathrm dy+x^3\,\mathrm dz=\int_{\mathcal C}\mathbf f\cdot\mathrm d\mathbf r$

with $\mathbf f=(y+7\sin x,z^2+9\cos y,x^3)$ .

By Stoke's theorem, the line integral is equivalent to the surface integral over $\mathcal S$ of the curl of $\mathbf f$ . We have

$\nabla\times\mathbf f=(-2z,-3x^2,-1)$

so the line integral is equivalent to

$\displaystyle\iint_{\mathcal S}\nabla\times\mathbf f\cdot\mathrm d\mathbf S$
$=\displaystyle\iint_{\mathcal S}\nabla\times\mathbf f\cdot\left(\dfrac{\partial\mathbf s}{\partial u}\times\dfrac{\partial\mathbf s}{\partial v}\right)\,\mathrm du\,\mathrm dv$

where $\mathbf s(u,v)$ is a vector-valued function that parameterizes $\mathcal S$ . In this case, we can take

$\mathbf s(u,v)=(u\cos v,u\sin v,2u^2\cos v\sin v)=(u\cos v,u\sin v,u^2\sin2v)$

with $0\le u\le1$ and $0\le v\le2\pi$ . Then

$\mathrm d\mathbf S=\left(\dfrac{\partial\mathbf s}{\partial u}\times\dfrac{\partial\mathbf s}{\partial v}\right)\,\mathrm du\,\mathrm dv=(2u^2\cos v,2u^2\sin v,-u)\,\mathrm du\,\mathrm dv$

and the integral becomes

$\displaystyle\iint_{\mathcal S}(-2u^2\sin2v,-3u^2\cos^2v,-1)\cdot(2u^2\cos v,2u^2\sin v,-u)\,\mathrm du\,\mathrm dv$
$=\displaystyle\int_{v=0}^{v=2\pi}\int_{u=0}^{u=1}u-6u^4\sin^3v-4u^4\cos v\sin2v\,\mathrm du\,\mathrm dv=\pi$ <span />

4 0

3 years ago

Express 192 as a prime factors in order

iVinArrow [24]

You can write this two ways - as a list of prime factors, or combine like factors and represent their quantity with an exponent.
If you begin by dividing by two, you can do that six times, with a three as the remaining prime factor.
2·2·2·2·2·2·3
OR
2∧6 · 3

7 0

4 years ago

Find the equation of the line. <br><br> GIVING BRAINIEST TO WHOEVER HELPS ME AND GETS IT RIGHT!!!

Anestetic [448]

Answer:

y= -3x + 7

Step-by-step explanation:

y intercept= 7

slope= -3

3 0

3 years ago

Read 2 more answers